Question

我从Google Talk帐户收到消息，它们显示在Ios模拟器的表视图中，但是当我发送它时，它不会显示在Google Talk客户端（在另一台计算机中）中。这是代码：

-(IBAction)sendchat:(id)sender
{
General *general = [General sharedManager];//It is a singleton class used to store some values that need to be accesible in the whole application.


NSXMLElement *body = [NSXMLElement elementWithName:@"body"];
text=[mensaje text];
NSLog(@"Texto en el body: %@", text);
[body setStringValue:text];
NSArray *dest=[general.firstfrom componentsSeparatedByString:@"/"];//in firstfrom is stored the account from wich we receive the first message. This app cannot start a conversation itself, must only answer

NSLog(@"Destination trimmed: %@", [dest objectAtIndex:0]);//Here, the destination account shows correctly (without the /xxxx stuff, just name@gmail.com)
XMPPMessage *mens=[[XMPPMessage alloc]init];
[mens addAttributeWithName:@"body" stringValue:text];
[mens addAttributeWithName:@"sender" stringValue:general.userlogin];
NSLog(@"text vale: %@", text);
NSXMLElement *messagetosend = [NSXMLElement elementWithName:@"message"];
[messagetosend addAttributeWithName:@"type" stringValue:@"chat"];
[messagetosend addAttributeWithName:@"to" stringValue:[dest objectAtIndex:0]];
[messagetosend addChild:body];
NSLog(@"We are sending to: %@", [dest objectAtIndex:0]);
[self.xmppStream sendElement:messagetosend];

[self xmppStream:xmppStream didReceiveMessage:mens];//manage the sent message as it was received, to show it in the Table View
self.mensaje.text=@"";
}

正如我所说，邮件收到完美，但我无法发送。我见过很多关于如何发送的例子，它们就像我的代码。如果我调试发件人它显示ok（namesender@gmail.com），“to”属性也可以（namereceiver@gmail.com）。 xmppStrem设置正确（据我所知）：

xmppStream = [[XMPPStream alloc] init];
[xmppStream addDelegate:self delegateQueue:dispatch_get_main_queue()];

在ViewDidLoad方法中。

有任何帮助吗？谢谢。

--- --- EDIT

我忘了说，这两个帐户都互相认识，而且在Google Talk客户端中，会发送状态。

Answer 1

我找到了答案。我有两个类接收消息，因为A类必须接收一条消息来触发推送B类视图（此应用程序无法自行启动聊天对话）。所以，我设置了两个xmppStream，每个类一个。我在我的General类中放了一个xmppStream，让两个类都接受xmppStream，它现在发送消息。

XMPPFramework消息未发送

1 个答案: