Question

function Person() {}
Person.prototype.population = 0;
Person.prototype.constructor = function(name) {
    this.name = name;
    console.log("Name: " + this.name);
    console.log("Population: " + (++this.population) );
}

var p = new Person("Wex");

以下代码似乎不起作用，虽然逻辑上我觉得它似乎听起来像。为什么这不显示名称和人口？

Answer 1

http://jsfiddle.net/zerkms/gvjEF/

var Person = function(name) {
    this.name = name;
    console.log("Name: " + this.name);
    console.log("Population: " + (++Person.population) );
};
Person.population = 0;

var p = new Person("Wex");
var p = new Person("Wex");

只要您需要静态类变量：

将其定义为classname.varname
使用类名来使用它，而不是this

Answer 2

试试这个：

function Person() {}
Person.staticProperty = "foo";
var obj = new Person();

staticProperty在Person对象中定义，它是函数。

使用原型模拟静态变量

2 个答案: