Question

所以我读完了Crawling with an authenticated session in Scrapy并且我被挂了，我99％确定我的解析代码是正确的，我只是不相信登录是重定向并且成功。

我也遇到了check_login_response（）的问题，不知道它正在检查哪个页面。虽然“注销”是有意义的。

======更新======

from scrapy.contrib.spiders.init import InitSpider
from scrapy.http import Request, FormRequest
from scrapy.contrib.linkextractors.sgml import SgmlLinkExtractor
from scrapy.contrib.spiders import Rule

from scrapy.spider import BaseSpider
from scrapy.selector import HtmlXPathSelector

from linkedpy.items import LinkedPyItem

class LinkedPySpider(InitSpider):
    name = 'LinkedPy'
    allowed_domains = ['linkedin.com']
    login_page = 'https://www.linkedin.com/uas/login'
    start_urls = ["http://www.linkedin.com/csearch/results?type=companies&keywords=&pplSearchOrigin=GLHD&pageKey=member-home&search=Search#facets=pplSearchOrigin%3DFCTD%26keywords%3D%26search%3DSubmit%26facet_CS%3DC%26facet_I%3D80%26openFacets%3DJO%252CN%252CCS%252CNFR%252CF%252CCCR%252CI"]

    def init_request(self):
        #"""This function is called before crawling starts."""
        return Request(url=self.login_page, callback=self.login)

    def login(self, response):
        #"""Generate a login request."""
        return FormRequest.from_response(response,
                    formdata={'session_key': 'user@email.com', 'session_password': 'somepassword'},
                    callback=self.check_login_response)

    def check_login_response(self, response):
        #"""Check the response returned by a login request to see if we aresuccessfully logged in."""
        if "Sign Out" in response.body:
            self.log("\n\n\nSuccessfully logged in. Let's start crawling!\n\n\n")
            # Now the crawling can begin..

            return self.initialized() # ****THIS LINE FIXED THE LAST PROBLEM*****

        else:
            self.log("\n\n\nFailed, Bad times :(\n\n\n")
            # Something went wrong, we couldn't log in, so nothing happens.

    def parse(self, response):
        self.log("\n\n\n We got data! \n\n\n")
        hxs = HtmlXPathSelector(response)
        sites = hxs.select('//ol[@id=\'result-set\']/li')
        items = []
        for site in sites:
            item = LinkedPyItem()
            item['title'] = site.select('h2/a/text()').extract()
            item['link'] = site.select('h2/a/@href').extract()
            items.append(item)
        return items

通过在self.initialized（）

前添加“Return”来解决问题

再次感谢！ -Mark

Answer 1

class LinkedPySpider(BaseSpider):

应该是：

class LinkedPySpider(InitSpider):

此外，您不应该覆盖我在答案中提到的parse功能：https://stackoverflow.com/a/5857202/crawling-with-an-authenticated-session-in-scrapy

如果您不了解如何定义提取链接的规则，请仔细阅读文档：
http://readthedocs.org/docs/scrapy/en/latest/topics/spiders.html#scrapy.contrib.spiders.Rule
http://readthedocs.org/docs/scrapy/en/latest/topics/link-extractors.html#topics-link-extractors

在使用Scrapy进行身份验证时抓取LinkedIn

1 个答案: