Question

我试图做一些事情，这可能非常简单，所以请耐心等待我，我只是想得到＆＃39; DisplayName＆＃39;从XML文件到我的C＃代码中的字符串。这就是我所拥有的：

这是VS2005中的C＃2.0

XML：

<MonitorScope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" id="System" xmlns="http://tempuri.org/XMLSchema.xsd">
    <PersonalSafety>    
<MonitorResponseRecord Enabled="false" DisplayName="ValveFailureAtCentralPosition">
<ExpressionMonitor>
<postAlarm>
<AlarmName>Valve_Position_Fault</AlarmName>
<Parameter1> Sensor Position = {X}</Parameter1>
<Parameter2> Sensor Position = {X}</Parameter2>
<Parameter3> Sensor Position = {X}</Parameter3>
</postAlarm>
</ExpressionMonitor>
</MonitorResponseRecord>
<MonitorResponseRecord ...  ... ...>
... ...
... ... and so on about 1600 times.

在我的C＃代码中，我尝试了以下内容，但无法使用： C＃：

public class AlarmRecord
{
    /// <remarks/>
    public string PmAlarm;

    /// <remarks/>
    public string Parameter1;

    /// <remarks/>
    public string Parameter2;

    /// <remarks/>
    public string Parameter3;

    /// <remarks/>
    public string DisplayName;
}

    protected void OnPostAlarm(PostAlarm postAlarm)
    {
        try 
        {
            AlarmRecord alarmRecord = new AlarmRecord(); 
            alarmRecord.PmAlarm    = postAlarm.AlarmName;
            alarmRecord.Parameter1 = postAlarm.Parameter1;
            alarmRecord.Parameter2 = postAlarm.Parameter2;
            alarmRecord.Parameter3 = postAlarm.Parameter3;

            string fileName = "UMSM.009.8Root.xml";
            string fullPath;
            fullPath = Path.GetFullPath(fileName);

            XmlTextReader reader = new XmlTextReader(new StringReader(fullPath));
            System.Xml.XPath.XPathDocument docNav = new System.Xml.XPath.XPathDocument(reader);

            System.Xml.XPath.XPathNavigator Q = docNav.CreateNavigator();
            System.Xml.XPath.XPathExpression EXE = Q.Compile("MonitorResponseRecord/@DisplayName");
            alarmRecord.DisplayName = Convert.ToString(Q.Evaluate(EXE));
             alarms.Enqueue( alarmRecord ); 
        }
        catch (Exception e)
        {
            Log.Write(e);
            OnUnknownResponse(postAlarm);
        }
    }

基本上我当前的问题是在调试问题时我注意到的问题是“阅读器”和＃39;阅读器＆＃39;初始化...程序通常会抛出异常

Answer 1

您可以使用XmlReader：

    protected void OnPostAlarm(PostAlarm postAlarm) 
    {
       AlarmRecord record = null;
       List<AlarmRecord> recordList = new List<AlarmRecord>();

        using(XmlReader reader = XmlReader.Create("Xml/bin/UMSM.009.8Root.xml"))
        {

            while (reader.Read())
            {
                if (reader.NodeType == XmlNodeType.Element)
                {
                    switch (reader.Name)
                    {
                        case "MonitorResponseRecord":
                            record = new AlarmRecord();
                            recordList.Add(record);
                            reader.MoveToAttribute("DisplayName");
                            record.DisplayName = reader.Value;
                            break;

                        case "AlarmName":
                            record.PmAlarm = reader.ReadString();
                            break;

                        case "Parameter1":
                            record.Parameter1 = reader.ReadString();
                            break;

                        case "Parameter2":
                            record.Parameter2 = reader.ReadString();
                            break;

                        case "Parameter3":
                            record.Parameter3 = reader.ReadString();
                            break;
                    }
                }
            }
        }

Answer 2

最好在.NET 2.0中使用XPathNavigator和XPath查询。读取属性（如示例中的DisplayName）是通过在XPath查询中使用@来完成的。

有一个不错的例子here。虽然XPathExpression位不是必需的，但您可以直接调用nav.Evaluate并提供字符串XPath查询。

示例XML（我需要删除命名空间属性）：

<MonitorScope>
<PersonalSafety>    
    <MonitorResponseRecord Enabled="false" DisplayName="ValveFailureAtCentralPosition">
        <ExpressionMonitor>
            <postAlarm>
                <AlarmName>Valve_Position_Fault</AlarmName>
                <Parameter1> Sensor Position = {X}</Parameter1>
                <Parameter2> Sensor Position = {X}</Parameter2>
                <Parameter3> Sensor Position = {X}</Parameter3>
            </postAlarm>
        </ExpressionMonitor>
    </MonitorResponseRecord>
</PersonalSafety>

使用XPath的代码示例：

        XmlDocument doc = new XmlDocument();
        doc.LoadXml(xml);

        XPathNavigator nav = doc.CreateNavigator();
        XPathNodeIterator nodeList = nav.Select("//MonitorScope/PersonalSafety/MonitorResponseRecord");

        if (nodeList.Count != 0) {
            foreach (XPathNavigator node in nodeList) {
                // node queries are relative to MonitorResponseRecord node
                string displayName = node.SelectSingleNode("./@DisplayName").Value;

                string alarmName = node.SelectSingleNode("ExpressionMonitor/postAlarm/AlarmName").Value;
                string param1 = node.SelectSingleNode("ExpressionMonitor/postAlarm/Parameter1").Value;
                string param2 = node.SelectSingleNode("ExpressionMonitor/postAlarm/Parameter2").Value;
                string param3 = node.SelectSingleNode("ExpressionMonitor/postAlarm/Parameter3").Value;

                // do something with values
            }
        }

如何将DisplayName放入变量

这是VS2005中的C＃2.0

2 个答案: