Question

我有一个脚本，我已经定义了两个数组。现在，根据传递的数组名称（作为参数），我想在下面的函数中处理相同的内容。早些时候，在使用${!}

之前，我甚至没有在变量'ARRAY'中获得任何元素

现在的问题是，当我打印数组内容（或该数组中的元素数量）时，我只得到第一个元素。

有什么建议吗？

脚本：

#!/bin/bash

APP=$1

process_data() {
    ARRAY="${!1}"
    echo "No of array elements: ${#ARRAY[@]}"
    echo "Array content: ${ARRAY[@]}"
}


ORADATA=(
"oraserver/content:abcDaily/ORAServer/"
"oraserver/w3s-ix86:abcDaily/ORAServer/"
)

SQLDATA=(
"sqlserver/content:abcDaily/SQLServer/"
"sqlserver/w3s-ix86:abcDaily/SQLServer/"
)

process_data ${APP[@]}

命令：

-bash-2.05b$ ./testarray.sh ORADATA

输出：

No of array elements: 1
Array content: oraserver/content:abcDaily/ORAServer/

Answer 1

以下是您修改过的脚本（在可怕的eval的帮助下）：

#!/bin/bash

APP=$1

process_data() {
   ARRAY=( $(eval echo \${$1[@]}) )
   echo "No of array elements: ${#ARRAY[@]}"
   echo "Array content: ${ARRAY[@]}"
}

ORADATA=(
"oraserver/content:abcDaily/ORAServer/"
"oraserver/w3s-ix86:abcDaily/ORAServer/"
)

SQLDATA=(
"sqlserver/content:abcDaily/SQLServer/"
"sqlserver/w3s-ix86:abcDaily/SQLServer/"
)

process_data ${APP[@]}

<强>输出：

No of array elements: 2
Array content: oraserver/content:abcDaily/ORAServer/ oraserver/w3s-ix86:abcDaily/ORAServer/

Answer 2

这是一个没有eval的版本（所以它正确处理数组值中的shell元字符）：

#!/bin/bash

APP=$1

process_data() {
    ARRAYVAR="$1[@]"   # This just textually appends "[@]" to $1
    ARRAY=("${!ARRAYVAR}")   # Use indirect expansion to get contents of array, store as new array
    echo "No of array elements: ${#ARRAY[@]}"
    echo "Array content: ${ARRAY[@]}"
}


ORADATA=(
"oraserver/content:abcDaily/ORAServer/"
"oraserver/w3s-ix86:abcDaily/ORAServer/"
)

SQLDATA=(
"sqlserver/content:abcDaily/SQLServer/"
"sqlserver/w3s-ix86:abcDaily/SQLServer/"
)

process_data $APP   # Note that APP is not an array, so the [@] bit was irrelevant

示例：

$ ./testarray.sh ORADATA
No of array elements: 2
Array content: oraserver/content:abcDaily/ORAServer/ oraserver/w3s-ix86:abcDaily/ORAServer/

无法检索所有数组元素

2 个答案: