Question

我有一个值为(0.7, 0.4, 0.1)的数组，我想用这段代码绘制相应的椭球：

from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np

fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')

u = np.linspace(0, 2 * np.pi, 100)
v = np.linspace(0, np.pi, 100)

x = 0.7 * np.outer(np.cos(u), np.sin(v))
y = 0.4 * np.outer(np.sin(u), np.sin(v))
z = 0.1 * np.outer(np.ones(np.size(u)), np.cos(v))
ax.plot_surface(x, y, z,  rstride=4, cstride=4, color='b')

plt.show()

当我绘制图形时，它看起来像一个比预期的椭球更多的球体。我想问题是设置轴的“正确”范围。

我怎么能解决这个“问题”？

Answer 1

您可以使用ax.set_xlim()，ax.set_ylim()和ax.set_zlim()方法设置适当的范围。

from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np

fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')

u = np.linspace(0, 2 * np.pi, 100)
v = np.linspace(0, np.pi, 100)

x = 0.7 * np.outer(np.cos(u), np.sin(v))
y = 0.4 * np.outer(np.sin(u), np.sin(v))
z = 0.1 * np.outer(np.ones(np.size(u)), np.cos(v))
ax.plot_surface(x, y, z,  rstride=4, cstride=4, color='b')
ax.set_xlim([-0.5, 0.5])
ax.set_ylim([-0.5, 0.5])
ax.set_zlim([-0.5, 0.5])

plt.show()

轴x y z的范围相同

1 个答案: