使用Spring 3.1在JSP页面中不显示表单验证错误

时间:2012-05-31 15:41:23

标签: java spring-mvc validation

我无法在JSP页面中显示验证错误消息。这是我的控制器:

@Controller
@RequestMapping("/secure")
@SuppressWarnings({"All"})
public class OperationController {

    @ModelAttribute("crawler/operation")
    public OperationForm operationForm() {
        return new OperationForm();
    }

    @RequestMapping(value = "crawler/operation/create", method = RequestMethod.POST)
    public String processCrawlerOperationForm(@Valid OperationForm operationForm, BindingResult result, Map model) {
        if (result.hasErrors()) {
            HashMap<String, String> errors = new HashMap<String, String>();
            for (FieldError error : result.getFieldErrors()) {
                errors.put(error.getField(), error.getDefaultMessage());
            }
            model.put("errors", errors);
            return "crawler/operation";
        }
        //Some logic
        return "crawler/operation";
    }

}

我100%确定错误退出。我一直在调试此代码以确保存在错误。

我的表单类:

public class OperationForm {

    @NotEmpty
    private String operationName;

    @NotEmpty
    private String author;

    @NotEmpty
    private String configurationId;

    public String getOperationName() {
        return operationName;
    }
    //Getters and setters
}

我的JSP弹簧形式:

<form:form action="${pageContext.servletContext.contextPath}/secure/crawler/operation/create.htm" commandName="crawler/operation">
    <table border="0" cellspacing="12">
        <tr>
             <td>
                 <spring:message code="application.operationForm.operationName"/>
             </td>
             <td>
                <form:input path="operationName"/>
             </td>
             <td class="error">
                <form:errors path="operationName"/>
             </td>
        </tr>
        <tr>
             <td>
                 <spring:message code="application.operationForm.author"/>
             </td>
             <td>
                <form:input path="author"/>
             </td>
             <td class="error">
                <form:errors path="author"/>
             </td>
        </tr>
        <tr>
             <td>
                 <spring:message code="application.operationForm.configuration"/>
             </td>
             <td>
                <form:input path="configurationId"/>
             </td>
             <td class="error">
                <form:errors path="configurationId"/>
             </td>
        </tr>
        <tr>
             <td>
                 <input class="button" type="submit" value="Vykdyti"/>
             </td>
        </tr>
    </table>
</form:form>

我做错了什么?

1 个答案:

答案 0 :(得分:2)

不是循环遍历错误列表并将它们插入到模型对象中,只需检查验证并返回视图,即

if(result.hasErrors())
  return "crawler/operation";
...

此外,在您的控制器方法中,添加@ModelAttribute注释,即

public String processCrawlerOperationForm(@ModelAttribute("form") @Valid OperationForm operationForm, BindingResult result, Map model)

当您最初显示表单时,确保ModelAttribute注释的值与您放入模型对象的值相匹配。如果您使用上面的方法operationForm来生成模型,请将其设置为该值的任何值。我将其更改为更有用的值,Spring可能会被/混淆,将其更改为简单的“形式”。