我想显示下面所有错误的列表,但是它一次只显示一个错误,是否有人知道为什么我的代码没有显示错误列表?下面是显示存储错误的数组的代码,用于说明如果没有错误会发生什么的代码,以及代码说明如果有错误会发生什么。
<?php
$getcourseid = (isset($_POST['courseid'])) ? $_POST['courseid'] : '';
$getcoursename = (isset($_POST['coursename'])) ? $_POST['coursename'] : '';
$getduration = (isset($_POST['duration'])) ? $_POST['duration'] : '';
$errors = array();
if (!$getcourseid){
$errors[] = "You must enter in Course's ID";
}else if (!$getcoursename){
$errors[] = "You must enter in Course's Name";
}else if (!$getduration){
$errors[] = "You must select Course's Duration";
}
if(!$errors) {
$insertsql = "
INSERT INTO Course
(CourseNo, CourseName, Duration)
VALUES
(?, ?, ?)
";
if (!$insert = $mysqli->prepare($insertsql)) {
// Handle errors with prepare operation here
}
$insert->bind_param("sss", $getcourseid, $getcoursename, $getduration);
$insert->execute();
if ($insert->errno) {
// Handle query error here
}
$insert->close();
// don't use $mysqli->prepare here
$query = "SELECT CourseNo FROM Course WHERE CourseNo = ?";
// prepare query
$stmt=$mysqli->prepare($query);
// You only need to call bind_param once
$stmt->bind_param("s",$getcourseid);
// execute query
$stmt->execute();
// get result and assign variables (prefix with db)
$stmt->bind_result($dbCourseId);
//get number of rows
$stmt->store_result();
$numrows = $stmt->num_rows();
}
if(empty($errors)) {
if ($numrows == 1){
$errormsg = "<span style='color: green'>Course " . $getcourseid . " - " . $getcoursename . " has been Created</span>";
$getcourseid = "";
$getcoursename = "";
$getduration = "";
}else{
$errormsg = "An error has occured, Course has not been Created";
}
} else {
if (count($errors) > 0)
{
foreach ($errors AS $Errors)
{
$errormsg = "{$Errors} <br>";
}
}
}
?>
**ADDITIONAL QUESTION:**
$form = "
<form action='" . htmlentities($_SERVER["PHP_SELF"]) . "' method='post'>
<table>
<tr>
<td></td>
<td id='errormsg'>$errormsg</td>
</tr>
<tr>
<td>Course ID:</td>
<td><input type='text' name='courseid' value='$getcourseid' /></td>
</tr>
<tr>
<td>Course Name:</td>
<td><input type='text' id='nameofcourse' name='coursename' value='$getcoursename' /></td>
</tr>
<tr>
<td>Duration (Years):</td>
<td>{$durationHTML}</td>
</tr>
<tr>
<td></td>
<td><input type='submit' value='Create Course' name='createbtn' /></td>
</tr>
</table>
</form>";
echo $form;
上面的表单位于此问题顶部的php代码下方。现在发生的是验证错误列表全部显示在表单的顶部。但我真正想要的是每个验证错误都低于它所指的表单功能。
例如,如果我没有填写“课程标识”文本输入,那么我希望验证错误"You must enter in Course's ID"
显示在“课程标识”文本输入下方。
如果我没有填写课程名称文本输入,那么我希望验证错误"You must enter in Course's Name"
显示在课程名称文本输入下方。
等。为了做到这一点,需要在代码中进行哪些更改?
答案 0 :(得分:1)
尝试
if (!$getcourseid){
$errors[] = "You must enter in Course's ID";
}
if (!$getcoursename){
$errors[] = "You must enter in Course's Name";
}
if (!$getduration){
$errors[] = "You must select Course's Duration";
}
答案 1 :(得分:1)
if (!$getcourseid)
{
$errors[] = "You must enter in Course's ID";
}
if (!$getcoursename)
{
$errors[] = "You must enter in Course's Name";
}
if (!$getduration)
{
$errors[] = "You must select Course's Duration";
}
答案 2 :(得分:1)
我还没有完成与你需要弄清楚的持续时间有关的代码我在这里给你一个输入courseid和coursename的逻辑。
<?php
$errors = array();
$getcourseid = "";
$getcoursename = "";
$errormsg = "";
if($_POST)
{
$getcourseid = $_POST['courseid'];
$getcoursename = $_POST['coursename'];
if (!$getcourseid){
$errors['course_id'] = "You must enter in Course's ID";
}if (!$getcoursename){
$errors['course_name'] = "You must enter in Course's Name";
}
}
if(!$errors && $_POST) {
$insertsql = "
INSERT INTO Course
(CourseNo, CourseName, Duration)
VALUES
(?, ?, ?)
";
if (!$insert = $mysqli->prepare($insertsql)) {
// Handle errors with prepare operation here
}
$insert->bind_param("sss", $getcourseid, $getcoursename, $getduration);
$insert->execute();
if ($insert->errno) {
// Handle query error here
}
$insert->close();
// don't use $mysqli->prepare here
$query = "SELECT CourseNo FROM Course WHERE CourseNo = ?";
// prepare query
$stmt=$mysqli->prepare($query);
// You only need to call bind_param once
$stmt->bind_param("s",$getcourseid);
// execute query
$stmt->execute();
// get result and assign variables (prefix with db)
$stmt->bind_result($dbCourseId);
//get number of rows
$stmt->store_result();
$numrows = $stmt->num_rows();
}
$getcourseid = (!empty($getcourseid))?$getcourseid:"";
$getcoursename = (!empty($getcoursename))?$getcoursename:"";
$durationHTML = (!empty($durationHTML))?$durationHTML:"";
$error_c_id = (!empty($errors['course_id']))?$errors['course_id']:"";
$error_c_name = (!empty($errors['course_name']))?$errors['course_name']:"";
$form = "
<form action='" . htmlentities($_SERVER["PHP_SELF"]) . "' method='post'>
<table>
<tr>
<td>Course ID:</td>
<td><input type='text' name='courseid' value='".$getcourseid."' />".$error_c_id."</td>
</tr>
<tr>
<td>Course Name:</td>
<td><input type='text' id='nameofcourse' name='coursename' value='".$getcoursename."' />".$error_c_name."</td>
</tr>
<tr>
<td>Duration (Years):</td>
<td>{$durationHTML}</td>
</tr>
<tr>
<td></td>
<td><input type='submit' value='Create Course' name='createbtn' /></td>
</tr>
</table>
</form>";
echo $form;
?>