用mysql连接

Question

我们正在尝试使用ajax和php在MySQL数据库和Google API之间进行接口（在第3行“phpsqlajax_dbinfo.php”中定义了数据库信息）。我们想用Google API的lat / long创建一个标记，但是我们在“add（Child）”上遇到致命错误 实际错误消息：“在非对象”

上调用成员函数addChild（）

我们如何让db注册并存储信息？

<?php

require_once("phpsqlajax_dbinfo.php");

$xml = ("mapPointInfo.xml") ;

$newLatLng = $_POST['latlng'];      //new markers LatLng
$newLatLng = substr($newLatLng, 1, -1);  //removes first and last characters of
newLatLng which are ( and )

list($newLat, $newLng) = explode(",", $newLatLng);


//$newLng = substr($newLng, 1, 0);

$locName = $_POST['geoNameMarker'];     //geocoded or simple incremented site name
$markerComment = $_POST['createMarker'];    //comment entered by user
$userName = $_POST['user'];         //acquire username from session
$voteValue = "likes";       //acquire vote value if any
date_default_timezone_set('America/New_York');
$timeStamp = date("m/d/Y G:i");         //get timestamp   
year:month:date:hour:minutes:seconds (example: 11:6:31:14:31:42)


if($markerComment == null || $markerComment == '' || $markerComment == ' '){
$markerComment = ' ';
}

$markerComment = htmlentities($markerComment, ENT_QUOTES);
$locName = htmlentities($locName, ENT_QUOTES);

$marker = $xml->addChild('marker');
$marker->addAttribute('lat', $newLat); 
$marker->addAttribute('lng', $newLng);
$marker->addAttribute('name', $locName); 
$marker->addAttribute('type', 'user-sug');


$comment = $marker->addChild('comment', $markerComment);   //add information to
latest/last marker
$comment->addAttribute('user', $userName); 
$comment->addAttribute('vote', 'likes');
$comment->addAttribute('time', $timeStamp); 


header('P3P:CP="IDC DSP COR ADM DEVi TAIi PSA PSD IVAi IVDi CONi HIS OUR IND CNT"');
header ('http://www.wmuhotspotmap.org/');
exit();

?>

Answer 1

致命错误？您收到 致命错误。它以前如何？我猜它与$xml是一个字符串这一事实有关，但你出于某种原因正在做$xml->addChild()，好像它是一个带有函数的对象。