Question

我有一个小问题！我想从我的mysql数据库中获取最后3行..（工作）

<?php
$sql = "SELECT id,title,description FROM news ORDER BY `id` DESC LIMIT 0, 3";
$result = mysql_query($sql);
while ($list = mysql_fetch_assoc($result)) 
{
?>
    <div class="one-of-three">
        <div class="box">
            <h2><?PHP echo ($list['id']);?> <?PHP echo (htmlentities($list['title'],ENT_QUOTES,'UTF-8'));?></h2>
            <div class="content clearfix">
                <p><?PHP echo (htmlentities($list['description'],ENT_QUOTES,'UTF-8'));?></p>
            </div>
        </div>
    </div>
<?php
}
?>

我的问题是html布局！我有3个div盒，我会漂浮..

    <div class="one-of-three">
        [...]
    </div>
    <div class="two-of-three">
        [...]
    </div>
    <div class="three-of-three">
        [...]
    </div>

但我的结果给了我

    <div class="one-of-three">
        [...]
    </div>
    <div class="one-of-three">
        [...]
    </div>
    <div class="one-of-three">
        [...]
    </div>

我尝试了不同的东西，但我不知道它是如何工作的:( 你可以给我一个提示吗？

Answer 1

你应该得到一个数组$numbers = array('one', 'two', 'three');。然后有一个变量$i = 0;并在循环中递增它。第一行应该是：<div class="<?php echo $numbers[$i++]; ?>-of-three">。

Answer 2

<?php
 $n = array(1 => 'one', 2 => 'two', 3 => 'three');
 while ($list = mysql_fetch_assoc($result)) {
?>
    <div class="<?php echo $n[$list['id']]; ?>-of-three">

各行中的mysql行

2 个答案: