Question

customer_i       fundamt      installment          date_time
41                 115        1054                 2014-05-27  
42                 116        1067                 2014-07-27  
41                 117        1089                 2014-07-30  
42                 118        1120                 2014-07-30   
43                 118        1120                 2014-08-30   
42                 118        1120                 2014-08-30   
41                 118        1120                 2014-06-30   
43                 118        1120                 2014-02-30

我想这样：

customer_id        fundamt    installment          date_time
41                 117        1089                 2014-07-30
42                 118        1120                 2014-08-30 
43                 118        1120                 2014-08-30

包含max date_time的行：

PLease帮助我在Mysql中编写SQL

Answer 1

彻底解决后，你的问题实现了实际要求。这可能是简单的查询，更易于阅读和维护。

SELECT * FROM your_table WHERE (customer_id, date_time) IN ( SELECT customer_id, MAX(date_time) FROM test GROUP BY customer_id ) 
ORDER BY customer_id

修改

我能想到的其他选择就是将自己加入桌子。

SELECT a.* FROM your_table a LEFT JOIN your_table b ON a.customer_id = b.customer_id AND a.date_time < b.date_time WHERE b.customer_id IS NULL

Answer 2

您可以在子句中使用子选择

SELECT customer_id, fundamt, installment, date_time
FROM your_table
where ( customer_id, date_time)  in (select customer_id , max(date_time) 
                      FROM your_table  
                      GROUP BY customer_id  )

在Mysql中打印具有单独最大日期的行

2 个答案: