结合数组和MySQL结果

时间:2012-05-26 19:16:51

标签: php mysql

我有一个使用数组来存储问题的测验:

$array=array(
        '1'=> array('1','What does everyone know when they see it?','quest1','Good     publicity','Bad punctuation', 'Good business writing', 'Bad spelling','../images/example03.jpg'),
        '2'=> array('2','What do people write instead of \'now\'?','quest2','Presently','At this moment in time', 'Currently', 'At the present time','../images/example03.jpg'),
);

然后我使用这个循环显示问题:

foreach($array as $quiz)
{
echo            
                '<div class="question">
                        <div class="questionList">
                            <h4>' . $quiz[0] . '. <strong>' . $quiz[1] .         '</strong></h4>
                                <ul>
                                    <li><input type="radio" name="' . $quiz[2] . '" value="1"> '. $quiz[3] . '</li>
                                    <li><input type="radio" name="' . $quiz[2] . '" value="2"> '. $quiz[4] . '</li>
                                    <li><input type="radio" name="' . $quiz[2] . '" value="3"> '. $quiz[5] . '</li>
                                    <li><input type="radio" name="' . $quiz[2] . '" value="4"> '. $quiz[6] . '</li>
                                </ul>
                        </div>
                    <img src="'. $quiz[7] . '" class="questionImg01" />
                    <div class="clr"></div>
                </div>
                ';
    }

}

如果有人第一次没有回答所有问题,我会将每个问题的值存储在MySQL中,如果没有答案则存储为“0”。我想检查一下用户已经回答的单选按钮,但是无法确定如何将测验数组和MySQL结果结合起来。

结果的表结构是:

quiz_id |用户名| quest1 | quest2 | quest3 | quest4 | quest5 | quest6 | quest7 | quest8 | quest9 | quest10 |完整

其中quiz_id是该测验的参考编号,而完成是一个标记,如果用户已回答所有问题则记录。我正在检索这样的结果:

$results = mysql_query("SELECT * FROM quiz_results_baseline WHERE username = ('$username')");

我有没有办法将这两者结合起来?

我也遇到了无法使此查询包含WHERE语句的问题 - 我想将所有测验结果存储在一个表中,然后使用quiz_id引用每个用户的测验结果:

mysql_query("INSERT INTO quiz_results_baseline (quest1,quest2,quest3,quest4,quest5,quest6,quest7,quest8,quest9,quest10,username,quiz_id,complete) VALUES $queryData ON DUPLICATE KEY UPDATE quest1=VALUES(quest1),quest2=VALUES(quest2),quest3=VALUES(quest3),quest4=VALUES(quest4),quest5=VALUES(quest5),quest6=VALUES(quest6),quest7=VALUES(quest7),quest8=VALUES(quest8),quest9=VALUES(quest9),quest10=VALUES(quest10),complete=VALUES(complete)");

任何帮助将不胜感激!

1 个答案:

答案 0 :(得分:0)

为了让您完成一半完成的测验结果以及测验,请尝试以下代码。

$questions=array(
  '1'=> array('1','What does everyone know when they see it?','quest1','Good     publicity','Bad punctuation', 'Good business writing', 'Bad spelling','../images/example03.jpg'),
  '2'=> array('2','What do people write instead of \'now\'?','quest2','Presently','At this moment in time', 'Currently', 'At the present time','../images/example03.jpg'),
);

// do your query for the row of answers
// $answers = mysql_fetch_assoc(...);

// for testing
$answers = array(
 'quest1' => '1',
 'quest2' => '4');


for($i = 1; $i <= count($questions); $i++)
{
  $quiz = $questions[$i];
  $answer = $answers[$quiz[2]];

  echo            
    '<div class="question">
        <div class="questionList">
          <h4>' . $quiz[0] . '. <strong>' . $quiz[1] . '</strong></h4>
          <ul>
            <li><input type="radio" name="' . $quiz[2] . '" value="1" ' . (($answer == '1') ? 'checked' : '') . '> '. $quiz[3] . '</li>
            <li><input type="radio" name="' . $quiz[2] . '" value="2" ' . (($answer == '2') ? 'checked' : '') . '> '. $quiz[4] . '</li>
            <li><input type="radio" name="' . $quiz[2] . '" value="3" ' . (($answer == '3') ? 'checked' : '') . '> '. $quiz[5] . '</li>
            <li><input type="radio" name="' . $quiz[2] . '" value="4" ' . (($answer == '4') ? 'checked' : '') . '> '. $quiz[6] . '</li>
          </ul>
        </div>
      <img src="'. $quiz[7] . '" class="questionImg01" />
      <div class="clr"></div>
    </div>
    ';
}

您必须执行查询以获取$answers数组,但我输入了一个示例,以便您了解如何使用结果。

我运行了代码,结果如下:

results

希望有所帮助!