我在数据库中有一个名为“favorites”的表,有3列(user_id,bookmarked_song_id,bookmark_tag),我想为当前用户获取所有Bookmarked_song_id。
$username = $this->session->userdata('username');
$uidq = mysql_query('SELECT user_id FROM users WHERE username="' . $username . '"');
$rq = mysql_fetch_assoc($uidq);
$user_id = $rq['user_id'];
$getfavq = mysql_query("SELECT * FROM favorites WHERE user_id=$user_id");
$favsr = mysql_fetch_array($getfavq); //contains all the information from the favorites database where user_id is the user_of the currently logged-in user
我不知道接下来要用什么...我希望有类似的东西:
foreach($favsr['bookmarked_song_id'] as $song_id) {
$getsongq = mysql_query("SELECT * FROM songs WHERE song_id=$song_id");
$getsongr = mysql_fetch_assoc($getsongq);
$singer = $getsongr['singer'];
$song_name = $getsongr['song_name'];}
显然这个方法是错误的,因为我得到:“为foreach()提供的参数无效”。能有人帮我收听歌曲吗?提前致谢。
答案 0 :(得分:0)
应该是这样的:
$favsr = mysql_fetch_array($getfavq, MYSQL_ASSOC);
foreach($favsr as $row) {
$songid = $row['bookmarked_song_id'];
...
}
答案 1 :(得分:0)
mysql_fetch_array只加载一行, 它应该是那样的
$getfavq = mysql_query("SELECT * FROM favorites WHERE user_id=$user_id");
while $favsr = mysql_fetch_array($getfavq);
{$songid=$favsr['bookmarked_song_id'];
$getsongq = mysql_query("SELECT * FROM songs WHERE song_id=$song_id");
$getsongr = mysql_fetch_array($getsongq);
$singer = $getsongr['singer'];
$song_name = $getsongr['song_name'];}
答案 2 :(得分:0)
您已将此标记为codeigniter
。如果您正在构建CodeIgniter应用程序,则应该使用CI的数据库库:
$username = $this->session->userdata('username');
//Select your user
$this->db->select('user_id');
$this->db->where('username', $username);
$this->db->limit(1);
$user_query = $this->db->get('users');
if($user_query->num_rows() > 0)
{
// We found a user
$user = $user_query->row(); // select a single row
// Grab this user's favorites
$this->db->where('user_id', $user->id);
$favorites_query = $this->db->get('favorites');
$songs = $favorites_query->result();
if($songs)
{
foreach($songs as $song)
{
$song_id = $song->bookmarked_song_id;
$tag = $song->bookmark_tag;
// Do stuff with data.
}
}
else
{
// No songs/favorites found, catch error
}
}
else
{
// No such user found, catch error
}
当然,最佳做法是将您的用户数据和收藏夹数据放在不同的模型中,但这应该适用于此。