Question

我是python的新手，我想知道如何使代码重复random.randint部分100次。

#head's or tail's

print("you filp a coin it lands on...")

import random

heads = 0
tails = 0


head_tail =random.randint(1, 2,)

if head_tail == 1:
    print("\nThe coin landed on heads")
else:
    print("\nThe coin landed on tails")

if head_tail == 1:
    heads += 1
else:
   tails += 1

flip = 0
while True :
    flip +=1
    if flip > 100:
        break



print("""\nThe coin has been fliped 100 times
it landed on heads""", heads, """times and tails""", tails,
"""times""")

input("Press the enter key to exit")

Answer 1

你可以使用列表理解在一行中完成所有操作：

flips = [random.randint(1, 2) for i in range(100)]

并计算这样的头/尾数：

heads = flips.count(1)
tails = flips.count(2)

或者更好：

num_flips = 100
flips = [random.randint(0, 1) for _ in xrange(num_flips)]
heads = sum(flips)
tails = num_flips - heads

Answer 2

首先，我会将while循环替换为：

for flip in xrange(100):
  ...

其次，要进行100次随机试验，请在循环体内移动randint()调用 - 以及您要执行100次的其他操作：

for flip in xrange(100):
  head_tail = random.randint(1, 2)
  ...

最后，我将如何完成整个事情：

heads = sum(random.randint(0, 1) for flip in xrange(100))
tails = 100 - heads

Answer 3

您将使用range(100)，因为您使用的是Python3.x，它会创建一个0到99之间的列表（100个项目）。它看起来像这样：

print("you flip a coin it lands on...")

import random

heads = 0
tails = 0


for i in xrange(100):
    head_tail = random.randint((1, 2))

    if head_tail == 1:
        print("\nThe coin landed on heads")
    else:
        print("\nThe coin landed on tails")

    if head_tail == 1:
        heads += 1
    else:
        tails += 1    


print("""\nThe coin has been fliped 100 times
it landed on heads""", heads, """times and tails""", tails,
"""times""")

input("Press the enter key to exit")

Answer 4

for flip in range(100):
    head_tail = random.randint(1, 2)

    if head_tail == 1:
        print("\nThe coin landed on heads")
    else:
        print("\nThe coin landed on tails")

    if head_tail == 1:
        heads += 1
    else:
        tails += 1

Answer 5

我是Python的新手，通常是编程，但我在1天的编程实践中创建了自己的代码库。硬币翻转编码练习是我现在研究的书中的第一个。我试图在互联网上找到解决方案，我发现了这个话题。

我知道要使用本主题中的任何代码，因为我以前的答案中使用的函数很少。

对于处于类似情况的任何人：请随意使用我的代码。

import random

attempts_no = 0
heads = 0
tails = 0

input("Tap any key to flip the coin 100 times")


while attempts_no != 100:
 number = random.randint(1, 2)
 attempts_no +=1
 print(number)
 if number == 1:
    heads +=1
 elif number ==2:
    tails +=1

print("The coin landed on heads", heads, "times")
print("The coin landed on heads", tails, "times")

python，重复random.randint？

5 个答案: