Question

这个游戏的这一点是将硬币翻转100次并记录头部或尾部。在100翻转结束时，程序应打印出翻转头尾的次数。程序只是在我运行时打印头，我觉得它是通过执行第一个elif子句而不是random.randint函数来实现的。

任何人都可以帮忙完成这个程序吗？

import random

print ('Coin flip game')
start = input('Press enter to flip the coin')
coin_flip = random.randint(1, 2)
heads = int(1)
tails = int(2)
heads = int(heads)
tails - int(tails)
count = 0
while coin_flip:
    count += 1
    if count == 100:
        break

    elif coin_flip == 1:
        print ('Heads')

    elif coin_flip == 2:
        print ('Tails')

Answer 1

尝试这样的事情：

import random

print("Welcome to the coin flipper!")

start = input('Press enter to flip the coin')
count = 0
while True:
    coin_flip = random.randint(1,2)
    count+=1

    if count >100:
        break

    if coin_flip == 1:
        print('Heads')

    elif coin_flip == 2:
        print("Tails")

这样循环的每次迭代，数字都会因为它在循环内部而改变

您也不需要分配以后甚至不使用的所有变量你应该使用while True:作为循环

Answer 2

您希望如何打印还不清楚。你可以这样做：

>>> import random
>>> print [['H', 'T'][random.randint(0, 1)] for _ in range(100)]
['T', 'T', 'T', 'H', 'T', 'T', 'H', 'H', 'H', 'H', 'T', 'H', 'T', 'H', 'T', 'H', 'H',
 'H', 'H', 'H', 'T', 'T', 'H', 'T', 'H', 'H', 'H', 'H', 'H', 'H', 'H', 'H', 'T', 'T',
 'H', 'H', 'H', 'H', 'H', 'H', 'H', 'H', 'H', 'H', 'H', 'H', 'H', 'H', 'H', 'H', 'H',
 'H', 'H', 'T', 'H', 'T', 'H', 'T', 'H', 'H', 'H', 'T', 'T', 'T', 'H', 'H', 'H', 'T',
 'H', 'H', 'T', 'T', 'H', 'H', 'H', 'H', 'H', 'H', 'H', 'T', 'T', 'T', 'H', 'T', 'T',
 'H', 'H', 'H', 'H', 'T', 'H', 'H', 'H', 'T', 'T', 'T', 'H', 'H', 'H', 'T',]

或：

>>> heads = sum(random.randint(0, 1) for _ in range(100))
>>> print "heads =", heads, ' tails =', 100 - heads
heads = 46  tails = 54

Answer 3

您的问题在这里：

while coin_flip: # coin_flip is set to 1 or 2
    ...

由于coin_flip设置为1或2，因此您的循环将是无限的，而重要的部分是coin_flip不会更改（您不会更新它）。

要解决此问题，您应该通过在循环中为其分配一个随机数来更新coin_flip：

while True: count += 1 coin_flip = random.randint(1, 2) # you need to "flip" coin inside the loop if count == 100: break elif coin_flip == 1: print ('Heads') elif coin_flip == 2: print ('Tails')

要计算头数，您可以使用heads和tails变量来跟踪：

heads = 0 tails = 0 while True: count += 1 coin_flip = random.randint(1, 2) # you need to "flip" coin inside the loop if count == 100: break elif coin_flip == 1: print ('Heads') heads += 1 elif coin_flip == 2: print ('Tails') tails += 1 print "Number of heads: %s, Number of tails: %s" % (heads, tails)

Answer 4

heads,tails,=0,0
import random
for i in range(100):
    a=random.randint(1,2)
        if(a%2==0):
            tails+=1
        else:
        heads+=1
print 'no. of heads in 100 flips,',heads
print 'no. of tails in 100 flips,',tails

试试这个

Answer 5

我知道这是几年前的事了，但我修正了Serials的代码来计算最后的正面和反面的总数：

import random

print("Welcome to the coin flipper!")

start = input('Press enter to flip the coin')
count = 0
heads = 0
tails = 0
while True:
    coin_flip = random.randint(1,2)
    count+=1

    if count >100:
        break

    if coin_flip == 1:
        print('Heads')
        heads += 1

    elif coin_flip == 2:
        print("Tails")
        tails += 1
print(f'''
Number of tails: {tails}
Number of times heads {heads}
''')

random.randint函数不起作用

5 个答案: