我上课了:
class ThisClass
{
private string a {get; set;}
private string b {get; set;}
}
我想使用Linq的Intersect和Except方法,即:
private List<ThisClass> foo = new List<ThisClass>();
private List<ThisClass> bar = new List<ThisClass>();
然后我分别填写两个列表。我想做,例如(我知道这不对,只是伪代码),以下内容:
foo[a].Intersect(bar[a]);
我该怎么做?
答案 0 :(得分:27)
也许
// returns list of intersecting property 'a' values
foo.Select(f => f.a).Intersect(bar.Select(b => b.a));
BTW属性a
应该是公开的。
答案 1 :(得分:23)
如果你想要一个你想要交叉的单个属性的列表,那么所有其他漂亮的LINQ解决方案都可以正常工作。
但!如果您想在整个班级上相交,那么结果是List<ThisClass>
而不是List<string>
,您将需要编写自己的相等比较器。
foo.Intersect(bar, new YourEqualityComparer());
与Except
相同。
public class YourEqualityComparer: IEqualityComparer<ThisClass>
{
#region IEqualityComparer<ThisClass> Members
public bool Equals(ThisClass x, ThisClass y)
{
//no null check here, you might want to do that, or correct that to compare just one part of your object
return x.a == y.a && x.b == y.b;
}
public int GetHashCode(ThisClass obj)
{
unchecked
{
var hash = 17;
//same here, if you only want to get a hashcode on a, remove the line with b
hash = hash * 23 + obj.a.GetHashCode();
hash = hash * 23 + obj.b.GetHashCode();
return hash;
}
}
#endregion
}
答案 2 :(得分:2)
foo.Select(x=>x.a).Intersect(bar.Select(x=>x.a))
答案 3 :(得分:2)
与交叉和比较相比,不确定这个速度,但是如何:
//Intersect
var inter = foo.Where(f => bar.Any(b => b.a == f.a));
//Except - values of foo not in bar
var except = foo.Where(f => !bar.Any(b => b.a == f.a));
答案 4 :(得分:0)
期望的效果究竟是什么?当您通过{{1}的唯一值标识两个a
实例时,是否需要获取由类中的所有ThisClass
组成的字符串列表或ThisClass
列表1}}?
如果是前者,@ lazyberezovksy和@Tilak的两个答案应该有效。如果是后者,则必须覆盖a
或IEqualityComparer<ThisClass>
,以便IEquatable<ThisClass>
知道是什么使Intersect
的两个实例等效:
ThisClass
然后你可以打电话:
private class ThisClass : IEquatable<ThisClass>
{
private string a;
public bool Equals(ThisClass other)
{
return string.Equals(this.a, other.a);
}
}
答案 5 :(得分:0)
我知道这已经过时了,但你也不能只是覆盖Equals&amp;关于类本身的GetHashCode? p>
class ThisClass
{
public string a {get; set;}
private string b {get; set;}
public override bool Equals(object obj)
{
// If you only want to compare on a
ThisClass that = (ThisClass)obj;
return string.Equals(a, that.a/* optional: not case sensitive? */);
}
public override int GetHashCode()
{
return a.GetHashCode();
}
}
答案 6 :(得分:-2)
您应该创建IEqualityComparer。您可以将IEqualityComparer传递给Intersect()方法。这将帮助您更轻松地获取List(与bar相交)。
var intersectionList = foo.Intersect(bar, new ThisClassEqualityComparer()).ToList();
class ThisClassEqualityComparer : IEqualityComparer<ThisClass>
{
public bool Equals(ThisClass b1, ThisClass b2)
{
return b1.a == b2.a;
}
public int GetHashCode(Box bx)
{
// To ignore to compare hashcode, please consider this.
// I would like to force Equals() to be called
return 0;
}
}