Question

我想通过按钮操作传递一个url，因为我有10个按钮，这些按钮是通过代码动态创建的，然后点击，然后为每个相应的按钮分配一个特定的URL。这是我的代码

NSString *linkUrl = [NSString stringWithFormat:@"%@",[AllrecordG objectForKey:@"Link"]];
[leftLabelG addTarget:self action:@selector(clickMe:linkUrl:) forControlEvents:UIControlEventTouchUpInside];

-(void)clickMe:(UIButton *)sender{
}

但是在这里我收到警告“未使用的变量linkUrl”。

我研究了不同的文章，但有人告诉我不可能通过参数linke。任何人都可以告诉我如何为每个按钮操作传递url以及如何检索这些值。在clickMe定义中。

提前致谢。

Answer 1

UIButton这样的子类：

<强> MyButton.h

@interface MyButton : UIButton
{
     NSString *_linkUrl;
}

@property (nonatomic, retain) NSString *linkUrl

<强> MyButton.m

@implementation MyButton
@synthesize linkUrl = _linkUrl

传递linkUrl：

NSString *linkUrl = [NSString stringWithFormat:@"%@",[AllrecordG objectForKey:@"Link"]];
[leftLabelG addTarget:self action:@selector(clickMe:) forControlEvents:UIControlEventTouchUpInside];
[leftLabelG setLinkUrl:linkUrl];

现在你可以在你的行动中得到linkUrl：

-(void)clickMe:(MyButton *)sender{
      NSString *url = sender.linkUrl;
}

Answer 2

将你的linkurl放在NSArray中;

NSArray *linkUrls = [NSArray arratWithObjects:@"link",@"blah",@"blah"........,nil];

然后将标记设置为按钮作为数组中的索引，然后

leftLabelG.tag = 1;
rightLabelG.tag = 2;

-(void)clickMe:(UIButton *)sender{
      NSString *url = [linkUrls objectAtIndex:sender.tag];
}

Answer 3

使用类别

- (void)addTarget:(id)target action:(SEL)action withObject:(id)object forControlEvents:(UIControlEvents)controlEvents;


-(void)addTarget:(id)target action:(SEL)action withObject:(id)object1 withObject:(id)object2 forControlEvents:(UIControlEvents)controlEvents {
SEL action_ = [self generateAction:action withObject:object1 withObject:object2];
IMP impl = imp_implementationWithBlock(^(id self_) {
    objc_msgSend(self_, action, self, [object1 copy], [object2 copy]);
});
class_replaceMethod([target class], action_, impl, "v@:@");

[self addTarget:target action:action_ forControlEvents:controlEvents];

}

如何在UiButton动作中传递任何类型的参数？

3 个答案: