如何使图像旋转看起来干净？ Android GL ES

Question

我正在读这本名为“开始安卓游戏”的书。

在书中，它在SpriteBatcher类中有以下方法......

public void drawSprite(float x, float y, float width, float height, float angle, TextureRegion region) {
    float halfWidth = width / 2;
    float halfHeight = height / 2;

    float rad = angle * Vector2.TO_RADIANS;
    float cos = FloatMath.cos(rad);
    float sin = FloatMath.sin(rad);

    float x1 = -halfWidth * cos - (-halfHeight) * sin;
    float y1 = -halfWidth * sin + (-halfHeight) * cos;
    float x2 = halfWidth * cos - (-halfHeight) * sin;
    float y2 = halfWidth * sin + (-halfHeight) * cos;
    float x3 = halfWidth * cos - halfHeight * sin;
    float y3 = halfWidth * sin + halfHeight * cos;
    float x4 = -halfWidth * cos - halfHeight * sin;
    float y4 = -halfWidth * sin + halfHeight * cos;

    x1 += x;
    y1 += y;
    x2 += x;
    y2 += y;
    x3 += x;
    y3 += y;
    x4 += x;
    y4 += y;

    verticesBuffer[bufferIndex++] = x1;
    verticesBuffer[bufferIndex++] = y1;
    verticesBuffer[bufferIndex++] = region.u1;
    verticesBuffer[bufferIndex++] = region.v2;

    verticesBuffer[bufferIndex++] = x2;
    verticesBuffer[bufferIndex++] = y2;
    verticesBuffer[bufferIndex++] = region.u2;
    verticesBuffer[bufferIndex++] = region.v2;

    verticesBuffer[bufferIndex++] = x3;
    verticesBuffer[bufferIndex++] = y3;
    verticesBuffer[bufferIndex++] = region.u2;
    verticesBuffer[bufferIndex++] = region.v1;

    verticesBuffer[bufferIndex++] = x4;
    verticesBuffer[bufferIndex++] = y4;
    verticesBuffer[bufferIndex++] = region.u1;
    verticesBuffer[bufferIndex++] = region.v1;

    numSprites++;
}

我的问题是如何平滑地旋转下面的图像，使图像中的线条看起来不像素化？

我的图像大小合适，DPI在旋转之前看起来很棒，但是当它旋转时，线条的边缘看起来不那么好。

Answer 1

您可以尝试使用LINEAR采样而不是NEAREST，但是如果没有看到问题的图片或看到纹理创建代码，我很难猜到更多。