Question

我需要从文件中删除所有非字母，小写或大写的内容，并将其替换为空格，例如：

The bear ate 3 snakes, then ate 50% of the fish from the river.

这变为：

The bear ate   snakes  then ate     of the fish from the river

有时文件包含不常见的字符。它保存为UTF-8。

如何用空格替换任何非字母？

Answer 1

如果你想支持unicode字母(as mentioned in your question)，那么这个perl命令可以替换所有unicode non-letters：

echo $line | perl -pe 's/[^\p{L}\s]+/ /g;'

参考：http://www.regular-expressions.info/unicode.html

Answer 2

$ echo "The bear ate 3 snakes, then ate 50% of the fish from the river." | sed "s/[^a-zA-Z]/ /g"
The bear ate   snakes  then ate     of the fish from the river

Answer 3

这可能对您有用：

echo 'The bear ate 3 snakes, then ate 50% of the fish from the river.' | 
tr -c '[:alpha:]' ' '
The bear ate   snakes  then ate     of the fish from the river

或：

echo 'The bear ate 3 snakes, then ate 50% of the fish from the river.' |
sed 's/[^[:alpha:]]/ /g'
The bear ate   snakes  then ate     of the fish from the river

Answer 4

尝试：

sed 's/[^A-Za-z]/ /g;' myfile.txt

如何用sed替换任何不带空格的字母？

4 个答案: