Question

我试图在php中替换以下字符串：

2011.11.12 20:06,Teal'c Ostus,Solid Pyroxeres 46521,Pyroxeres

使用：

2011.11.12 20:06,Teal'c Ostus,Solid Pyroxeres,46521,Pyroxeres

注意：这里有5个逗号分隔值

Time, Character, Item Type, Quantity, Item Group

请注意，仍然会留下一些空格，例如日期和时间以及名字和名字以及名称中包含多个单词的项目。

此外，它不能取代\ r和\ n，因为有很多行，如上面的

Answer 1

以下是搜索的正则表达式：

(\d{4}\.\d{2}\.\d{2}\s\d{2}:\d{2},[^,]*,\D*)\s(\d{5},.*)

替换正则表达式

$1,$2

<强>解释

搜索正则表达式

(       Begin a numbered capture group (Nameless and accessed via index)  
\d{4}   Means: capture digits with exact 4 repititions  
\.      Capture a dot (You have to escape it with a backslash, if not it means capture all  
        characters except linefeed)
\d{2}   Capture 2 digits
\.      Capture a dot
\d{2}   Capture 2 digits
\s      Capture 1 whitespace
\d{2}   Capture 2 digits
:       Capture a colon
\d{2}   Capture 2 digits
,       Capture a comma
[^,]*   Capture everything except a comma with 0 to infinity repititions
,       Capture a comma
\D*     Capture everything except a digit with 0 to infinity repititions
)       Close first capture group
\s      Capture a whitespace
(       Begin a numbered capture group
\d{5}   Capture 5 digits
,       Capture a comma
.*      Capture everything except a linebreak
)       Close second capture group

替换的正则表达式

$1      Insert capture group number 1
,       Insert a comma
$2      Insert capture group number 2

我希望这能解释正则表达式的一些（有用但有时令人困惑）“魔力”。设计和测试正则表达式的好工具叫做Expresso，可以找到here。如果你想要一个带有表达式测试器的在线帮助和正则表达式库，你会发现它here

Answer 2

您可以使用此

$result = preg_replace('/(?<=[a-z_])\s+(?=\d)|(?<=\d)\s+(?=[a-z_])/i', ',', $subject);

<强>解释

                # Match either the regular expression below (attempting the next alternative only if this one fails)
   (?<=            # Assert that the regex below can be matched, with the match ending at this position (positive lookbehind)
      [a-z_]          # Match a single character present in the list below
                         # A character in the range between “a” and “z”
                         # The character “_”
   )
   \s              # Match a single character that is a “whitespace character” (spaces, tabs, and line breaks)
      +               # Between one and unlimited times, as many times as possible, giving back as needed (greedy)
   (?=             # Assert that the regex below can be matched, starting at this position (positive lookahead)
      \d              # Match a single digit 0..9
   )
|               # Or match regular expression number 2 below (the entire match attempt fails if this one fails to match)
   (?<=            # Assert that the regex below can be matched, with the match ending at this position (positive lookbehind)
      \d              # Match a single digit 0..9
   )
   \s              # Match a single character that is a “whitespace character” (spaces, tabs, and line breaks)
      +               # Between one and unlimited times, as many times as possible, giving back as needed (greedy)
   (?=             # Assert that the regex below can be matched, starting at this position (positive lookahead)
      [a-z_]          # Match a single character present in the list below
                         # A character in the range between “a” and “z”
                         # The character “_”
   )

Answer 3

在Perl中你可以使用：

$line =~ s/([A-Za-z])\s+(\d)/$1,$2/g;

Answer 4

你没有说你正在使用什么语言，但这样的事情应该有效：

搜索：([A-Za-z]) (\d) 替换：\1,\2

Answer 5

怎么样：

$str = "2011.11.12 20:06,Teal'c Ostus,Solid Pyroxeres 46521,Pyroxeres";
$str = preg_replace('/(\D+) (\d+)/', "$1,$2", $str);
echo $str;

<强>输出：

2011.11.12 20:06,Teal'c Ostus,Solid Pyroxeres,46521,Pyroxeres

用逗号替换字母和数字之间的空格

5 个答案: