Question

表1：

ID      Total1 Total2 Total3
1         10       0          20
1         40       0          50
1         15       0          5

表2：

ID     Total

1        140

如何累加所有行并在table2中找到匹配的总数？

如何累加所有行并在table2中找到NOT匹配的总数并写入update语句来更新（添加那些）并写入table2？

select sum(t1.total1) + sum(t1.total2) +sum(t1.total3) as "Total" from
table t1, table t2 where t1.ID=t2.ID and  sum(t1.total1) +
sum(t1.total2) +sum(t1.total3)=t2.total;

我无法正确理解更新语法。

Answer 1

看起来您有正确的查询来查找总计并将其匹配。要更新总数不同的行，可以使用相关的子查询，如下所示：

UPDATE table2
SET total = (
   SELECT SUM(Total1 + Total2 + Total3) FROM table1
   WHERE id = table2.id
   GROUP BY id
)

或者使用连接（稍微复杂一些，但可能更快）

UPDATE t2
SET t2.total = t1.total
FROM table2 t2
INNER JOIN (
   SELECT id, SUM(Total1 + Total2 + Total3) as total FROM table1
   GROUP BY id
) t1 ON t1.id = t2.id
WHERE t2.total <> t1.total

Answer 2

select T1.* from
(
    select t1.ID, sum(t1.total1) + sum(t1.total2) + sum(t1.total3) as Total
    from table t1
    group by t1.ID
) t1
inner join table t2 on t1.ID = t2.ID and t1.Total = t2.total

累积条件查询

2 个答案: