Question

嘿，我正在使用oracle sql来创建数据库。

我现在正在处理查询，我想出了两个单独的quires，我想合并以获得结果。

我创建的第一个查询是查找演出所产生的总金额：

    SELECT SUM(bookings * CategoryPrice )AS Total_Money_Made
    FROM ( SELECT CategoryPrice , count(*) AS bookings
       FROM Booking b
       JOIN performance per
         ON b.performanceid =  per.performanceid
       JOIN Production p
         ON per.productionid = p.productionid          
      WHERE per.performanceid IN (1, 2, 3, 4)
      GROUP BY CategoryPrice)

这给了我一个结果：

TOTAL_MONEY_MADE

       337.5

然后我有另一个问题，计算出总特许权资金：

              SELECT SUM(ConsessionAmount * 2) AS Total_Consession_Money
      FROM( SELECT COUNT (*) AS ConsessionAmount
FROM Booking 
WHERE 
Consession = 'Yes' AND PerformanceID = '1' OR 
Consession = 'Yes' AND PerformanceID = '2' OR 
Consession = 'Yes' AND PerformanceID = '3' OR 
Consession = 'Yes' AND PerformanceID = '4' )

这给了我以下结果：

TOTAL_CONSESSION_MONEY

现在我想要一种方法，我可以从第一个查询中减去第二个查询的结果。可能吗？我该怎么办？我认为它与子查询有关，但我不太确定。

有任何帮助吗？感谢。

Answer 1

你可以这样做：

WITH TOTAL_MADE
AS
(   
    SELECT SUM(bookings * CategoryPrice )AS Total_Money_Made
    FROM ( SELECT CategoryPrice , count(*) AS bookings
       FROM Booking b
       JOIN performance per
         ON b.performanceid =  per.performanceid
       JOIN Production p
         ON per.productionid = p.productionid          
      WHERE per.performanceid IN (1, 2, 3, 4)
      GROUP BY CategoryPrice)
), TOTAL_CONSESSION
AS
(
    SELECT SUM(ConsessionAmount * 2) AS Total_Consession_Money
      FROM( SELECT COUNT (*) AS ConsessionAmount
    FROM Booking 
    WHERE 
    Consession = 'Yes' AND PerformanceID = '1' OR 
    Consession = 'Yes' AND PerformanceID = '2' OR 
    Consession = 'Yes' AND PerformanceID = '3' OR 
    Consession = 'Yes' AND PerformanceID = '4' )
)
SELECT
    TOTAL_CONSESSION.Total_Consession_Money-
    TOTAL_MADE.Total_Money_Made AS Something
FROM
    TOTAL_MADE,
    TOTAL_CONSESSION;

Answer 2

您可以使用括号

在select语句中选择

select (put your second query here) - (put your first select here) from dual

Answer 3

尝试使用以下内容：

SELECT Total_Money_Made - Total_Consession_Money FROM

( SELECT SUM(bookings * CategoryPrice )AS Total_Money_Made, ( SELECT SUM(ConsessionAmount * 2) AS Total_Consession_Money
      FROM( SELECT COUNT (*) AS ConsessionAmount
FROM Booking 
WHERE 
Consession = 'Yes' AND PerformanceID = '1' OR 
Consession = 'Yes' AND PerformanceID = '2' OR 
Consession = 'Yes' AND PerformanceID = '3' OR 
Consession = 'Yes' AND PerformanceID = '4' )
    FROM ( SELECT CategoryPrice , count(*) AS bookings
       FROM Booking b
       JOIN performance per
         ON b.performanceid =  per.performanceid
       JOIN Production p
         ON per.productionid = p.productionid          
      WHERE per.performanceid IN (1, 2, 3, 4)
      GROUP BY CategoryPrice) )

合并两个选择查询sql

TOTAL_MONEY_MADE

TOTAL_CONSESSION_MONEY

3 个答案: