我想实现这两个函数,以便我能够输入和输出我的类的对象。我得到了>>运营商工作但不是那么多<<。
这是我的.h文件中的代码:
class MyString
{
public:
MyString();
MyString(char *message);
~MyString();
void Print();
void Copy(MyString& rhs);
int Length();
MyString& operator()(const int index, const char b);
char& operator()(const int i);
MyString& operator=(const MyString& rhs);
bool operator==(const MyString& other) const;
bool operator!=(const MyString& other) const;
const MyString operator+(const MyString& rhs) const;
MyString& operator+=(const MyString& rhs);
private:
char *String;
int Size;
};
istream& operator>>(istream& input, MyString& rhs);
ostream& operator<<(ostream& output, const MyString& rhs);
以下是我的.cpp文件中两个函数的代码:
MyString::MyString()
{
char temp[] = "Hello World";
int counter(0);
while(temp[counter] != '\0') {
counter++;
}
Size = counter;
String = new char [Size];
for(int i=0; i < Size; i++)
String[i] = temp[i];
}
MyString::MyString(char *message)
{
int counter(0);
while(message[counter] != '\0') {
counter++;
}
Size = counter;
String = new char [Size];
for(int i=0; i < Size; i++)
String[i] = message[i];
}
MyString::~MyString()
{
delete [] String;
}
int MyString::Length()
{
int counter(0);
while(String[counter] != '\0')
{
counter ++;
}
return (counter);
}
const MyString MyString::operator+(const MyString& rhs) const
{
char* tmp = new char[Size + rhs.Size +1];
for(int i = 0; i < Size; i++)
{
tmp[i] = String[i];
}
for(int i = 0; i < rhs.Size+1; i++)
{
tmp[i+Size] = rhs.String[i];
}
const MyString MyString::operator+(const MyString& rhs) const
{
char* tmp = new char[Size + rhs.Size +1];
for(int i = 0; i < Size; i++)
{
tmp[i] = String[i];
}
for(int i = 0; i < rhs.Size+1; i++)
{
tmp[i+Size] = rhs.String[i];
}
MyString result;
delete [] result.String;
result.String = tmp;
result.Size = Size+rhs.Size;
return result;
}
MyString& MyString::operator()(const int index, const char b)
{
if(String[index] == '\0')
{
exit(1);
}
else
{
String[index] = b;
}
}
MyString& MyString::operator=(const MyString& rhs)
{
if(this != &rhs)
{
delete [] String;
String = new char[rhs.Size];
Size = rhs.Size;
for(int i = 0; i < rhs.Size+1 ; i++)
{
String[i] = rhs.String[i];
}
}
return *this;
}
void MyString::Copy(MyString& rhs)
{
delete [] String;
Size = rhs.Size;
String = new char[rhs.Size];
String = rhs.String;
}
MyString& MyString::operator+=(const MyString& rhs)
{
char* tmp = new char[Size + rhs.Size + 1];
for(int i = 0; i < Size; i++)
{
tmp[i] = String[i];
}
for(int i = 0; i <rhs.Size+1; i++)
{
tmp[i+Size] = rhs.String[i];
}
delete [] String;
String = tmp;
Size += rhs.Size;
return *this;
}
bool MyString::operator!=(const MyString& other) const
{
return !(*this == other);
}
bool MyString::operator==(const MyString& other)const
{
if(other.Size == this->Size)
{
for(int i = 0; i < this->Size+1; i++)
{
if(&other == this)
return true;
}
}
else
return false;
}
char& MyString::operator()(const int i)
{
if( String[i] == '\0')
{
exit(1);
}
else
{
return String[i];
}
}
void MyString::Print()
{
for(int i=0; i < Size; i++)
cout << String[i];
cout << endl;
}
istream& operator>>(istream& input, MyString& rhs)
{
char* temp;
int size(256);
temp = new char[size];
input.getline(temp,size);
rhs = MyString(temp);
delete [] temp;
return input;
}
ostream& operator<<(ostream& output, const MyString& rhs)
{
char* p;
int size(256);
p = new char[size];
output << rhs.MyString(p);
delete [] p;
return output;
}
以下是main.cpp文件中的调用方式:
cin >> SearchString >> TargetString; // Test of cascaded string-extraction operator<</*
if(SearchString.Find(ConstString) != -1) {
cout << ConstString << " is not in " << SearchString << endl; }
else {
cout << ConstString << " is in " << SearchString << endl;
cout << "Details of the hit: " << endl;
cout << "Starting poisition of the hit: " << SearchString.Find(ConstString) << endl;
cout << "The matching substring is: " << SearchString.Substring(SearchString.Find(ConstString), ConstString.length()); }
再次,cin&gt;&gt;运算符完美运行,但请帮我弄清楚如何输出字符串。
答案 0 :(得分:2)
不确定你在问什么。实现取决于您希望如何输出字符串。
对于某些原始输出,代码很可能如下所示:
output << rhs.get_data();