Question

我试图在一个非常简单的Hibernate示例中填充一些实体对象。我的数据库由两个表组成，“部门”（Id，Name）和“Employees”（Id，DepartmentsId，FirstName，LastName）。我的SQL查询只是Employees与Departments的左连接。

我已经设置了Hibernate documentation中指定的注释，但每当我尝试序列化实体时，Hibernate进入无限循环并最终抛出StackOverFlowError异常。回答我的另一个问题的人能够确定堆栈溢出正在发生，因为“Department”对象包含一组“Employee”对象，每个对象都包含一个“Department”对象，其中包含一组Employee对象等。等

根据上面链接的文档，这种类型的双向关系应该是合法的（Department中的“mappedBy”参数应该提供Hibernate;我也尝试使用在“注释”中注释掉的“joinColumn”注释下面的代码），以及我读过的其他内容表明Hibernate 假设足够聪明，不会在这种情况下进入无限循环，但它不适合我的例子。如果我通过从Employee类中删除Department对象将双向关系更改为单向关系，一切正常，但显然这会导致丢失大量功能。

我还尝试了旧版xml映射文件的注释，并为子表设置了“inverse”参数，但它仍然会产生同样的问题。我怎样才能使这种双向关系按照预期的方式运行？

系：

package com.test.model;

import java.util.HashSet;
import java.util.Set;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.FetchType;
import javax.persistence.GeneratedValue;
import javax.persistence.JoinTable;

import static javax.persistence.GenerationType.IDENTITY;
import javax.persistence.Id;
import javax.persistence.OneToMany;
import javax.persistence.Table;
import javax.persistence.JoinColumn;

import org.hibernate.Hibernate;
import org.hibernate.proxy.HibernateProxy;

@Entity
@Table(name="Departments"
,catalog="test"
)
public class Department implements java.io.Serializable {

 private Integer id;
 private String name;
 public Set<Employee> employees = new HashSet<Employee>(0);

public Department() {
}


public Department(String name) {
    this.name = name;
}
public Department(String name, Set employees) {
   this.name = name;
   this.employees = employees;
}

 @Id @GeneratedValue(strategy=IDENTITY)


@Column(name="Id", unique=true, nullable=false)
public Integer getId() {
    return this.id;
}

public void setId(Integer id) {
    this.id = id;
}


@Column(name="Name", nullable=false)
public String getName() {
    return this.name;
}

public void setName(String name) {
    this.name = name;
}

@OneToMany(fetch=FetchType.LAZY, mappedBy="department")
/*@OneToMany
@JoinColumn(name="DepartmentsId")*/
public Set<Employee> getEmployees() {
    return this.employees;
}

public void setEmployees(Set employees) {
    this.employees = employees;
}
}

员工：

package com.test.model;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.FetchType;
import javax.persistence.GeneratedValue;
import javax.persistence.JoinTable;

import static javax.persistence.GenerationType.IDENTITY;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.ManyToOne;
import javax.persistence.Table;

@Entity
@Table(name="Employees"
,catalog="test"
)
public class Employee  implements java.io.Serializable {


 private Integer id;
 private Department department;
 private String firstName;
 private String lastName;

public Employee() {
}

public Employee(Department department, String firstName, String lastName) {
   this.department = department;
   this.firstName = firstName;
   this.lastName = lastName;
}

 @Id @GeneratedValue(strategy=IDENTITY)


@Column(name="Id", unique=true, nullable=false)
public Integer getId() {
    return this.id;
}

public void setId(Integer id) {
    this.id = id;
}

@ManyToOne
@JoinColumn(name="DepartmentsId", nullable=false, insertable=false, updatable=false)
public Department getDepartment() {
    return this.department;
}

public void setDepartment(Department department) {
    this.department = department;
}


@Column(name="FirstName", nullable=false)
public String getFirstName() {
    return this.firstName;
}

public void setFirstName(String firstName) {
    this.firstName = firstName;
}


@Column(name="LastName", nullable=false)
public String getLastName() {
    return this.lastName;
}

public void setLastName(String lastName) {
    this.lastName = lastName;
}
}

部门经理（包含HQL查询）：

package com.test.controller;

import java.util.Collections;
import java.util.List;

import java.util.Iterator;

import org.hibernate.Criteria;
import org.hibernate.Hibernate;
import org.hibernate.HibernateException;
import org.hibernate.Query;
import org.hibernate.Session;

import com.test.model.Department;
import com.test.util.HibernateUtil;

public class DepartmentManager extends HibernateUtil {
public List<Department> list() {
    Session session = HibernateUtil.getSessionFactory().getCurrentSession();
    session.beginTransaction();
    List<Department> set = null;
    try {
        Query q = session.createQuery("FROM Department d JOIN FETCH d.employees e");
        q.setResultTransformer(Criteria.DISTINCT_ROOT_ENTITY);
        set = (List<Department>) q.list();
    } catch (HibernateException e) {
        e.printStackTrace();
        session.getTransaction().rollback();
    }
    session.getTransaction().commit();
    return set;
}
}

Answer 1

通常，您不应序列化您的实体。循环依赖和代理使得这很难。相反，您应手动将需要发送的数据传输到DTO（新的仅数据类），并将其序列化。它不会有懒惰的集合，代理和诸如此类的东西。

Answer 2

为了补充最高响应，我做了一个通用转换，谁为我做了工作，将实体值转移到DTO对象，你只需要从映射实体中创建具有相同名称的dto字段。

这是源代码。

/ ** * Atribui os valores de campos Correspondentes de um objeto para um outro objeto de destino。口 * campos do objeto de destino que ja estiverem preenchidos nao serao substituidos * * @param objetoOrigem * @param objetoDestino * @return * @throws NegocioException * /

public static <T1, T2> T2  convertEntity(T1 objetoOrigem, T2 objetoDestino) throws NegocioException {

    if (objetoOrigem != null && objetoDestino != null) {
        Class<? extends Object> classe = objetoOrigem.getClass();
        Class<? extends Object> classeDestino = objetoDestino.getClass();

        Field[] listaCampos = classe.getDeclaredFields();
        for (int i = 0; i < listaCampos.length; i++) {
            Field campo = listaCampos[i];
            try {
                Field campoDestino = classeDestino.getDeclaredField(campo.getName());
                campo.setAccessible(true);
                campoDestino.setAccessible(true);
                atribuiValorAoDestino(objetoOrigem, objetoDestino, campo, campoDestino);
            } catch (NoSuchFieldException e) {
                LOGGER.log(Logger.Level.TRACE, (Object) e);
                continue;
            } catch (IllegalArgumentException | IllegalAccessException e) {
                LOGGER.error(e.getMessage(), e);
                throw new NegocioException(e.getMessage(), EnumTypeException.ERROR);
            }
        }
    }
    return objetoDestino;
}

在获取双向集合时如何避免Hibernate中的无限循环？

2 个答案: