所以我想将一个简单的制表符分隔文本文件转换为csv文件。如果我使用string.split('\ n')将txt文件转换为字符串,我会得到一个列表,每个列表项都是一个字符串,每列之间有'\ t'。我以为我可以用逗号替换'\ t'但是它不会像字符串那样处理列表中的字符串并允许我使用string.replace。这是我的代码的开始,仍然需要一种方法来解析选项卡“\ t”。
import csv
import sys
txt_file = r"mytxt.txt"
csv_file = r"mycsv.csv"
in_txt = open(txt_file, "r")
out_csv = csv.writer(open(csv_file, 'wb'))
file_string = in_txt.read()
file_list = file_string.split('\n')
for row in ec_file_list:
out_csv.writerow(row)
答案 0 :(得分:41)
csv
支持制表符分隔文件。提供delimiter
argument to reader
:
import csv
txt_file = r"mytxt.txt"
csv_file = r"mycsv.csv"
# use 'with' if the program isn't going to immediately terminate
# so you don't leave files open
# the 'b' is necessary on Windows
# it prevents \x1a, Ctrl-z, from ending the stream prematurely
# and also stops Python converting to / from different line terminators
# On other platforms, it has no effect
in_txt = csv.reader(open(txt_file, "rb"), delimiter = '\t')
out_csv = csv.writer(open(csv_file, 'wb'))
out_csv.writerows(in_txt)
答案 1 :(得分:1)
为什么在使用csv
模块读取文件时应始终使用'rb'模式:
Python 2.7.2 (default, Jun 12 2011, 15:08:59) [MSC v.1500 32 bit (Intel)] on win32
Type "help", "copyright", "credits" or "license" for more information.
示例文件中包含的内容:任何旧垃圾,包括通过从数据库中提取blob或其他内容获得的控制字符,或在Excel公式中不明智地使用CHAR
函数,或者......
>>> open('demo.txt', 'rb').read()
'h1\t"h2a\nh2b"\th3\r\nx1\t"x2a\r\nx2b"\tx3\r\ny1\ty2a\x1ay2b\ty3\r\n'
Python在文本模式下读取文件时遵循CP / M,MS-DOS和Windows:\r\n
被识别为行分隔符,并提供为\n
和{{1} }又名Ctrl-Z被识别为END-OF-FILE标记。
\x1a
使用'rb'打开文件的csv按预期工作:
>>> open('demo.txt', 'r').read()
'h1\t"h2a\nh2b"\th3\nx1\t"x2a\nx2b"\tx3\ny1\ty2a' # WHOOPS
但是文字模式没有:
>>> import csv
>>> list(csv.reader(open('demo.txt', 'rb'), delimiter='\t'))
[['h1', 'h2a\nh2b', 'h3'], ['x1', 'x2a\r\nx2b', 'x3'], ['y1', 'y2a\x1ay2b', 'y3']]
答案 2 :(得分:0)
这就是我的做法
import csv
with open(txtfile, 'r') as infile, open(csvfile, 'w') as outfile:
stripped = (line.strip() for line in infile)
lines = (line.split(",") for line in stripped if line)
writer = csv.writer(outfile)
writer.writerows(lines)