我需要调用一个查询并获取一些事件的数量。换句话说,我需要一个CodeIgnıter方法,以便查询产生类似的东西:
SELECT COUNT( * ) AS total FROM comments WHERE `level`= 4
答案 0 :(得分:7)
$this->db->select('count(*)');
$this->db->from('comments');
$this->db->where('level','4');
$query = $this->db->get();
echo $query->num_rows();
答案 1 :(得分:3)
$this->db->select('count(*) as total');
$this->db->from('comments');
$this->db->where('level', 4);
$sql = $this->db->return_query();
/*debug*/
/*echo 'sql:: '.$sql;*/
$query = $this->db->get();
$arr = $query->row_array();
$total = $arr['total'];
答案 2 :(得分:2)
$query = $this->db->query("SELECT COUNT(*) AS total FROM comments WHERE `level`= 4");
echo $query->result_array();
或强>
$this->db->query("SELECT COUNT(*) AS total FROM comments");
$this->db->where("`level`= 4");
答案 3 :(得分:1)
您可以随时使用
$this->db->query('SELECT COUNT( * ) AS total FROM comments WHERE `level`= 4');
答案 4 :(得分:1)
我想你会喜欢这样的:
$count = $this->db->where("level","4")->count_all_results("comments");
http://codeigniter.com/user_guide/database/active_record.html