Question

我必须创建将继续审核我的表的触发器。触发器应该在插入和更新时执行。

目前我有两个触发器

一个用于插入：

CREATE TRIGGER SCH.TRG_TBL1_AFT_I
  AFTER INSERT ON SCH.TBL1  
  REFERENCING
    NEW AS n
  FOR EACH ROW
 MODE DB2SQL
INSERT INTO SCH.TBL1_AUDIT
VALUES( .. ,, .. );

另一个更新

CREATE TRIGGER SCH.TRG_TBL1_AFT_U
  AFTER UPDATE ON SCH.TBL1  
  REFERENCING
    NEW AS n
  FOR EACH ROW
 MODE DB2SQL
INSERT INTO SCH.TBL1_AUDIT
VALUES( .. ,, .. );

但问题是，如果可以在DB2中创建单个触发器来执行任务吗？ [提供两者，触发器正在做同样的事情。]

Answer 1

试试这个

CREATE or replace TRIGGER PASSENGER_TR01_BEFORE_IUD
 BEFORE 
    DELETE
 OR UPDATE OF FIRST_NAME 
 OR INSERT ON PASSENGER
REFERENCING 
OLD AS oldRow
NEW AS newRow
FOR EACH ROW
WHEN (1=1) 
Begin
Declare ACTION Char(1) Default '';
-- Use Case/When to inquire trigger-event
Case 
When INSERTING Then
    Set ACTION='I';
When UPDATING  Then
    Set ACTION='U';    
When DELETING  Then
    Set ACTION='D';    
Else
    Set ACTION='N';    
End Case;

-- Use If/Then/Else to inquire trigger-event
If INSERTING Then
    Set ACTION='I';
ElseIf UPDATING  Then
    Set ACTION='U';
ElseIf DELETING  Then
    Set ACTION='D';
Else
    Set ACTION='N';    
End If;
End

Answer 2

是的，这是可能的。的 See the documentation of create trigger 即可。这是一个粘贴：

trigger-event

   .-OR--------------------------------------.   
   V                                     (4) |   
|----+-INSERT--------------------------+-----+------------------|
     +-DELETE--------------------------+         
     '-UPDATE--+---------------------+-'         
               |     .-,-----------. |           
               |     V             | |           
               '-OF----column-name-+-'

这会让你说：

create trigger blah before insert on blah or update of blah。

Answer 3

此功能现在位于DB2 10.x版本中。它已经可用正弦9.7.x

Answer 4

You can find more info here

 CREATE OR REPLACE TRIGGER SET_SALARY
 NO CASCADE
 BEFORE UPDATE OR INSERT ON employee
 REFERENCING NEW AS n OLD AS o
 FOR EACH ROW
 WHEN( o.edlevel IS NULL OR n.edlevel > o.edlevel )
 BEGIN
    -- Give 10% raise to existing employees with new education level.
 IF UPDATING THEN SET n.salary = n.salary * 1.1;
     -- Give starting salary based on education level.
 ELSEIF INSERTING THEN
     SET n.salary = CASE n.edlevel WHEN 18 THEN 50000
  WHEN 16 THEN 40000
         ELSE 25000
  END;
  END IF;
 END

Answer 5

很抱歉，DB2没有提供将更新和插入触发器组合在一起的方法。

在DB2中，是否可以只为更新和插入提供一个触发器？

5 个答案: