Question

我遇到了SOAP序列化的问题，找到答案会很棒。这是一个非常简单的例子：

public void Test()
{
    StringBuilder sb = new StringBuilder();
    StringWriter writer = new StringWriter(sb);

    SoapReflectionImporter importer = new SoapReflectionImporter();
    XmlTypeMapping map = importer.ImportTypeMapping(typeof(A));
    XmlSerializer serializer = new XmlSerializer(map);
    serializer.Serialize(writer, new A());
}

[Serializable]
public class A
{
    public A()
    {
        BB = new B();
    }

    public int a;

    public B BB;
}
[Serializable]
public class B
{
    public int A1 { get; set; }

    public int A2 { get; set; }
}

如果我运行方法Test（），那么我得到以下异常：System.InvalidOperationException: Token StartElement in state Epilog would result in an invalid XML document.

感谢任何帮助。

Answer 1

请注意，如果流的位置未设置为流的开头，则上面的示例将不起作用。像这样：

Stream s = new MemoryStream();
XmlWriter writer = new XmlTextWriter(s, Encoding.UTF8);

SoapReflectionImporter importer = new SoapReflectionImporter();
XmlTypeMapping map = importer.ImportTypeMapping(typeof(A));
XmlSerializer serializer = new XmlSerializer(map);
writer.WriteStartElement("root");
serializer.Serialize(writer, new A());

s.Position = 0;
StreamReader sr = new StreamReader(s);
string data = sr.ReadToEnd();

Answer 2

使用XmlWriter而不是StringWriter并执行writer.WriteStartElement（“root”）;

这将有效：

Stream s = new MemoryStream();
XmlWriter writer = new XmlTextWriter(s, Encoding.UTF8);

SoapReflectionImporter importer = new SoapReflectionImporter();
XmlTypeMapping map = importer.ImportTypeMapping(typeof(A));
XmlSerializer serializer = new XmlSerializer(map);
writer.WriteStartElement("root");
serializer.Serialize(writer, new A());

StreamReader sr = new StreamReader(s);
string data = sr.ReadToEnd();

复杂类型的SOAP序列化时出现InvalidOperationException

2 个答案: