DESERIALIZE上的InvalidoperationException

Question

我想将XML反序列化为一个对象，但不断得到以下异常

System.InvalidOperationException: There is an error in XML document (0, 0).     ---> System.Xml.XmlException: Root element is missing.
   at System.Xml.XmlTextReaderImpl.Throw(Exception e)
at System.Xml.XmlTextReaderImpl.ParseDocumentContent()
at System.Xml.XmlTextReaderImpl.Read()
at System.Xml.XmlTextReader.Read()
at System.Xml.XmlReader.MoveToContent()
at   Microsoft.Xml.Serialization.GeneratedAssembly.XmlSerializationReaderBAObjectSchema.Read18_BAObjectSchema()
   --- End of inner exception stack trace ---
   at System.Xml.Serialization.XmlSerializer.Deserialize(XmlReader xmlReader, String encodingStyle, XmlDeserializationEvents events)
   at System.Xml.Serialization.XmlSerializer.Deserialize(TextReader textReader)
   at Siemens.BASys.BAObjectCreator.SchemaHandler.Deserialize[T](String path, Boolean throwException) in ....\SchemaHandler.cs:line 34

我正在使用的代码

` public static T Deserialize<T>(string path, bool throwException)
    {

        T root = default(T);
        try
        {
            using (FileStream fs = new FileStream(path, FileMode.Open))
            {
                using (TextReader reader = new StreamReader(fs))
                {
                    //XmlSerializer serializer = new XmlSerializer(typeof(T));
                    XmlSerializer serializer = new XmlSerializer(typeof(T));
                    root = (T)serializer.Deserialize(reader);
                }

            }
        }
        catch (Exception e)
        {
            System.Diagnostics.Debug.WriteLine(e.ToString());
        }
        return root;
    }`

我使用的XML看起来正确但不确定为什么会出现错误

以下是XML

的示例部分

<?xml version="1.0" encoding="utf-8"?>
<ObjectSchema>
  <Controllers>



  </Controllers>
</ObjectSchema>

任何帮助将不胜感激

由于

Answer 1

代码和XML没有任何问题。这是因为StreamReader。流是只有前向模式的读者一旦达到EOF，当尝试从状态EOF 读取相同的流时，XMLSerializer会抛出错误，即在文件末尾找到光标并且没有根标签

而不是使用允许多个读数的TextReader用户XMLTextReader。

using (FileStream fs = new FileStream(path, FileMode.Open))
 {
    using (XmlReader reader = new XmlTextReader(fs))
      {
         XmlSerializer serializer = new XmlSerializer(typeof(T));
         root = (T)serializer.Deserialize(reader);
      }

 }