Where子句返回满足三个条件中至少两个的值

时间:2012-04-09 21:05:52

标签: sql sql-server-2008 where-clause

我正在尝试编写一个where子句,该子句将找到满足三个条件中至少两个的人。 这是一个例子

   SELECT *
   FROM Personal
   WHERE
   [State] = 'Tx' or [City] = 'Austin' or [Gender] = 'Male'

所以它应该归还任何住在德克萨斯州和奥斯汀或生活在德克萨斯州并且是男性等等的人,但不是那些只住在德克萨斯州的人,他们必须满足至少两个标准

我的真实查询可以有更多标准,还包括大于两个或恰好两个等等。

提前致谢

2 个答案:

答案 0 :(得分:4)

您可以在一系列案例中添加匹配...然后另外还有0个结束语句,并将最终结果与所需匹配项的数量进行比较:

   SELECT *
   FROM Personal
   WHERE
     case when [State] = 'Tx' then 1 else 0 end
     + case when [City] = 'Austin' then 1 else 0 end
     + case when [Gender] = 'Male' then 1 else 0 end
     >= 2

或者,您可以将其分解为union all列表:

SELECT *
FROM   personal
       INNER JOIN (SELECT id
                   FROM   (SELECT id
                           FROM   personal
                           WHERE  state = 'Tx'
                           UNION ALL
                           SELECT id
                           FROM   personal
                           WHERE  city = 'Austin'
                           UNION ALL
                           SELECT id
                           FROM   personal
                           WHERE  gender = 'Male') a
                   GROUP  BY id
                   HAVING COUNT (*) >= 2) a
         ON personal.id = a.id 

答案 1 :(得分:1)

 SELECT *
   FROM Personal
   WHERE
   ([State] = 'Tx' AND [City] = 'Austin') or ([State] = 'Tx' AND [Gender] = 'Male')