Question

我有一张这样的表：

Table1
site | value
a | banana
b | banana
c | banana
a | fred
c | quetzal
a | quetzal

假设我有一组包含网站值的行

a
b
c

如何找到表1中的哪些值包含网站的a，b和c中的所有三个？

我知道

SELECT value
FROM Table1
WHERE site IN (SELECT site FROM chosen_sites)

将返回至少一个所选站点的所有值，但如何选择这三个中的值？

Answer 1

在我的脑海中，我想是这样的：

select t.value
from Table1 t
join chosen_sites s on s.site = t.site
group by t.value
having count(distinct t.site) = (select count(*) from chosen_sites)

修改：seems to work。

Answer 2

您可以cross join使用网站和left join table1的所有不同值，并检查计数。

select v.value
from table2 t2 --this is your table2 with all sites
cross join (select distinct value from table1) v
left join table1 t1 on t1.site=t2.site and t1.value=v.value
group by v.value
having count(t2.site)=count(t1.site)

SQL - 返回满足所有条件的值

2 个答案: