Question

您好我正在尝试解析从android发送的django中的JSON数组从android发送的json响应看起来像

 [{"record":[{"intensity":"Low","body_subpart":"Scalp","symptom":"Agitation"}]}]

现在我在django中的功能如下：

record = simplejson.loads(request.POST['record'])
for o in record:            
    new_symptoms=UserSymptoms(health_record=new_healthrecord,body_subpart=o.body_subpart,symptoms=o.symptom,intensity=o.intensity)
    new_symptoms.save()

但它不起作用给我发错误为此，我也尝试在python shell

中执行上面的行

>>>rec=json.loads('[{"intensity":"Low","body_subpart":"Scalp","symptom":"Agitation"},{"intensity":"High","body_subpart":"Scalp","symptom":"Bleeding"}]')
>>> for o in rec:
...     print rec.body_subpart
... 
Traceback (most recent call last):
  File "<console>", line 2, in <module>
AttributeError: 'list' object has no attribute 'body_subpart'

Answer 1

>>>rec=json.loads('[{"intensity":"Low","body_subpart":"Scalp","symptom":"Agitation"},{"intensity":"High","body_subpart":"Scalp","symptom":"Bleeding"}]')
>>> for o in rec:
...     print rec['body_subpart']

默认情况下，JSON对象转换为Python dict，因此令人惊讶的是您以这种方式管理访问其值的原因：

record = simplejson.loads(request.POST['record'])
for o in record:            
    body_subpart=o.body_subpart

Answer 2

您必须使用o['body_subpart']代替o.body_subpart。虽然这在Javascript中是相同的，但它在Python中是不同的。

解析django中的json数组

2 个答案: