我已经成功合并了3个表(使用ID),但是当我尝试添加第4个表时 - 输出完全混乱(值变得不现实/错误)所以我认为我与事实有关,这个第4个表有未分组的ID,所以我需要在加入这个新表之前对它们进行分组。现在查询如下:
SELECT name, SUM(money) AS MONEY
FROM transactions
JOIN results ON transactions.id = results.id
JOIN more ON results.per_id = more.per_id
GROUP BY name
HAVING SUM(money)>500
当我加入新表时:
SELECT name, SUM(money) AS MONEY, SUM(data_from_NT1), SUM(data_from_NT2)
FROM transactions
JOIN results ON transactions.id = results.id
JOIN more ON results.per_id = more.per_id
JOIN newtable ON results.per_id = newtable.per_id
GROUP BY name
HAVING SUM(money)>500
是否可以执行命令GROUP BY per_id:
(JOIN newtable ON results.per_id = newtable.per_id GROUP BY per_id)
在将此新表添加到主表之前?上面的行不起作用。
答案 0 :(得分:1)
您可以将group by
移动到子查询:
join (
select per_id
, sum(col1) as col1_avg
, avg(col2) as col2_avg
from newtable
group by
per_id
) as newtable
on results.per_id = newtable.per_id
如果您对per_id
进行分组,则必须汇总任何其他列。
答案 1 :(得分:1)
是的,这是可能的,但您必须将其写为SELECT。这是可能答案的第一个版本:
SELECT name,
SUM(money) AS money,
SUM(nt2.data_from_NT1) AS data_from_NT1,
SUM(nt2.data_from_NT2) AS data_from_NT2
FROM transactions AS t
JOIN results AS r ON t.id = r.id
JOIN more AS m ON r.per_id = m.per_id
JOIN (SELECT per_id, SUM(data_from_NT1) AS data_from_NT1, SUM(data_from_NT2) AS data_from_NT2
FROM newtable GROUP BY per_id
) AS nt2 ON results.per_id = nt2.per_id
GROUP BY name
HAVING SUM(money) > 500;
目前还不完全清楚你是否需要SUMs' SUMs'在主选择列表中;你可能不会。它还不清楚name
或money
列的来源;我通常也会在它们前面添加适当的表别名。有了这些警告,这可能更接近你所追求的目标:
SELECT name, SUM(money) AS MONEY, nt2.data_from_NT1, nt2.data_from_NT2
FROM transactions AS t
JOIN results AS r ON t.id = r.id
JOIN more AS m ON r.per_id = m.per_id
JOIN (SELECT per_id, SUM(data_from_NT1) AS data_from_NT1, SUM(data_from_NT2) AS data_from_NT2
FROM newtable GROUP BY per_id
) AS nt2 ON results.per_id = nt2.per_id
GROUP BY name, nt2.data_from_NT1, nt2.data_from_NT2
HAVING SUM(money) > 500;
毫无疑问,还有其他方法可以写出来。主查询中的分组可能更好地放入并行子查询中,在主查询中留下简单的直接连接。但我们没有掌握实际为您做的信息。