我有一张表staff
staff
pt | ward
P | 1
P | 1
T | 1
P | 2
T | 2
我想制作一张表格,计算每个病房的P和T的数量,如下所示:
staff
ward | P | T
1 | 2 | 1
2 | 1 | 1
我试过这个
WITH cte(ward, P, T) AS(
SELECT ward,
(SELECT COUNT(PT) FROM staff WHERE PT = 'P' ),
(SELECT COUNT(PT) FROM staff WHERE PT = 'T' ) FROM staff GROUP BY ward)
SELECT * FROM cte
然后我得到了这张桌子
staff
ward | P | T
1 | 3 | 2
2 | 2 | 2
任何帮助将不胜感激
答案 0 :(得分:1)
案例陈述将在此处起作用:
SELECT
ward,
SUM(CASE WHEN pt = P THEN 1 ELSE 0 END) AS P,
SUM(CASE WHEN pt = T THEN 1 ELSE 0 END) AS T
FROM
table
GROUP BY
ward
答案 1 :(得分:0)
使用条件聚合:
select ward, sum( (pt = 'P')::int ) as p, sum ( (pt = 'T')::int ) as t
from t
group by ward;