设置套接字接收超时

时间:2012-04-07 15:54:55

标签: java sockets timeout udp

我想将数据发送到服务器,然后等待一分钟的答案,然后关闭套接字。

怎么做?

 DatagramPacket sendpack = new ......;
 socket.send(pack);
 DatagramPacket recievepack = new .....;
 //wait 1 minute{
 socket.recieve(buf);
 //wait 1 minute}
 socket.close();

3 个答案:

答案 0 :(得分:21)

你可以试试这个。根据场景中的需要更改套接字的超时!此代码将发送消息,然后等待接收消息,直到达到超时!

DatagramSocket s;

    try {
        s = new DatagramSocket();
        byte[] buf = new byte[1000];
        DatagramPacket dp = new DatagramPacket(buf, buf.length);
        InetAddress hostAddress = InetAddress.getByName("localhost");

        String outString = "Say hi";        // message to send
        buf = outString.getBytes();

        DatagramPacket out = new DatagramPacket(buf, buf.length, hostAddress, 9999);
        s.send(out);        // send to the server

        s.setSoTimeout(1000);   // set the timeout in millisecounds.

        while(true){        // recieve data until timeout
            try {
                s.receive(dp);
                String rcvd = "rcvd from " + dp.getAddress() + ", " + dp.getPort() + ": "+ new String(dp.getData(), 0, dp.getLength());
                System.out.println(rcvd);
            }
            catch (SocketTimeoutException e) {
                // timeout exception.
                System.out.println("Timeout reached!!! " + e);
                s.close();
            }
        }

    } catch (SocketException e1) {
        // TODO Auto-generated catch block
        //e1.printStackTrace();
        System.out.println("Socket closed " + e1);

    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

答案 1 :(得分:8)

如果您使用的是DatagramSocketSocket,则可以使用

socket.setSoTimeout(1000); 
//the value is in milliseconds

对于任何细节,您应该查看DatagramSocket javadocSocket javadoc

答案 2 :(得分:1)

为了澄清EJP的评论,这就是“缺少break”导致SocketException的意思。

String group = "224.0.0.0";
int port = 5000;

MulticastSocket recvSock = new MulticastSocket(port);
recvSock.joinGroup(InetAddress.getByName(group));
recvSock.setSoTimeout(1000);

while(true) {
    try {
        recvSock.receive(in);               
    } catch (SocketTimeoutException e) {
        break;  // Closing here would cause a SocketException
    }
}

// Move the close() outside the try catch bloock
recvSock.leaveGroup(InetAddress.getByName(group));
recvSock.close();