我想从databas获取name = jiten的行 但是语法错误可以让任何人告诉我什么是正确的语法 获得单行 这是我的数据库类代码
public void getdata()
{
Cursor cursor = myDataBase.query("emp", new String[] {"email","name"}, " name='jiten'",new String[]{}, null, null, null);
Log.e("running", "cursor run");
if(cursor!=null)
{
Log.e("running", "curosr is not null");
while(cursor.moveToFirst())
{
Log.e("running", "curosr while loop enter");
String temp = (cursor.getString(cursor.getColumnIndex(email)));
String temp2 =(cursor.getString(cursor.getColumnIndex(name)));
Log.e("running", "id email" +temp+ " name"+temp2);
}
}
}
答案 0 :(得分:3)
您缺少selectionArgs
public Cursor query (String table, String[] columns, String selection, String[] selectionArgs, String groupBy, String having, String orderBy, String limit)
您可以在选择中包含?,它将被值替换 来自selectionArgs,以便它们出现在选择中。该 值将绑定为字符串。
http://developer.android.com/reference/android/database/sqlite/SQLiteDatabase.html
在你的情况下,它将是: Cursor cursor = myDataBase.query("emp", new String[] {"email","name"}, "name=?",new String[]{"jiten"}, null, null, null);