我在android开发中使用SQLite。当我使用insert插入一行时,我得到行的编号。但是,我想要KEY_ID,它是表的主键。我使用了下面的功能,但我得到了:
Caused by: java.lang.IllegalStateException: get field slot from row 0 col -1 failed
at android.database.CursorWindow.getLong_native(Native Method)
at android.database.CursorWindow.getInt(CursorWindow.java:434)
at android.database.AbstractWindowedCursor.getInt(AbstractWindowedCursor.java:93)
at winterfarmer.timemama.DataBaseAdapter.insertData(DataBaseAdapter.java:89)
at winterfarmer.timemama.ManagerActivity.addNewRecord2DB(ManagerActivity.java:106)
at winterfarmer.timemama.ManagerActivity.addNewRecord(ManagerActivity.java:100)
at winterfarmer.timemama.ManagerActivity.addNewRecord2DB(ManagerActivity.java:106)
at winterfarmer.timemama.ManagerActivity.addNewRecord(ManagerActivity.java:100)
at winterfarmer.timemama.ManagerActivity.setRecordOK(ManagerActivity.java:92)
at winterfarmer.timemama.ManagerActivity.setRecord(ManagerActivity.java:78)
at winterfarmer.timemama.ManagerActivity.onActivityResult(ManagerActivity.java:64)
at android.app.Activity.dispatchActivityResult(Activity.java:3890)
at android.app.ActivityThread.deliverResults(ActivityThread.java:3511)
我该如何修复这个错误?
public int insertData(RecordInfo recordInfo) {
Log.d(TAG, "insertData");
ContentValues initialValues = new ContentValues();
initialValues.put(KEY_HOUR, recordInfo.hour);
initialValues.put(KEY_MINUTE, recordInfo.minute);
initialValues.put(KEY_REPEAT, recordInfo.repeat);
long rowId = db.insert(DB_ALARM_TABLE, null, initialValues);
assert rowId >= 0 : "insertData failed";
Log.d(TAG, "insertData, rowId = " + rowId);
Cursor cur = db.rawQuery("SELECT last_insert_rowid() from "
+ DB_ALARM_TABLE, null);
cur.moveToFirst();
int colId = cur.getColumnIndex(KEY_ID);
Log.d(TAG, "insertData, colId = " + colId);
assert colId >= 0 : "insertData failed";
return cur.getInt(colId);
}
答案 0 :(得分:2)
从Cursor doc:
public abstract int getColumnIndex(String columnName)
自:API级别1 返回给定列的从零开始的索引 name,如果列不存在,则返回-1。如果您希望该列存在 改为使用getColumnIndexOrThrow(String),这将使错误更加清晰
这样可以更好地解释问题。
无论如何,回到实际问题:
问题是KEY_ID
不是您的选择查询的结果列(结果不会被命名为KEY_ID
,即使该值最初来自KEY_ID
列)。它只有一个列结果,因此请求列索引没有意义。 colId
将为0.您可以直接执行:
Cursor cur = db.rawQuery("SELECT last_insert_rowid() from "
+ DB_ALARM_TABLE, null);
cur.moveToFirst();
return cur.getInt(0);
答案 1 :(得分:0)
int colId = cur.getColumnIndex(KEY_ID);
我建议将其更改为
int colId = cur.getColumnIndexOrThrow(KEY_ID);
如果该列不存在,这似乎是可能的原因(正如Guillaume指出的那样),您将获得更多信息异常,并且比检查-1
返回值更简单。< / p>