是否可以使用父键和鉴别器值映射一对一的关系?我知道代码首先不喜欢具体类上的discriminator属性,只能在Map方法中引用它。
FlightTypes { Inbound = 1, Outbound = 2}
public class Transaction
- int TransactionId
- int? InboundFlightId
- InboundTransactionFlight InboundFlight
- int? OutboundFlightId
- OutboundTransactionFlight OutboundFlight
public abstract class TransactionFlight
- TransactionFlightId
public class InboundTransactionFlight : Flight
- List<Transaction> InboundFor
public class OutboundTransactionFlight : Flight
- List<Transaction> OutboundFor
Entity<InboundTransactionFlight>().Map(m => m.Requires("FlightTypeId").HasValue(1));
Entity<OutboundTransactionFlight>().Map(m => m.Requires("FlightTypeId").HasValue(2));
/ *这是当前生成的内容* /
CREATE TABLE Transactions (
TransactionId int NOT NULL,
InboundFlightId int NULL,
OutboundFlightId int NULL
)
CREATE TABLE TransactionFlights (
TransactionFlightId int NOT NULL,
FlightTypeId int NOT NULL,
...
CONSTRAINT PK_TransactionFlights PRIMARY KEY CLUSTERED ( TransactionFlightId )
)
/ *是否可以生成/映射并保持继承? * /
CREATE TABLE Transactions (
TransactionId int NOT NULL,
)
CREATE TABLE TransactionFlights (
TransactionId int NOT NULL,
FlightTypeId int NOT NULL,
...
CONSTRAINT PK_TransactionFlights PRIMARY KEY CLUSTERED ( TransactionId, FlightTypeId )
)
感谢。
答案 0 :(得分:3)
据我所知,这是不可能的,因为EF不允许在任何其他映射中使用discriminator列。此外,您的目标映射将要求您的事务类也具有FlightTypeId
属性(类必须具有整个键的属性)但它会破坏继承的含义,因为您将能够更改该属性的值并且使你的继承不一致。