我有一个图片框。 在图片框中,我使用以下方式画线:
gfx.DrawLine(nPen, line.xBegin, line.yBegin, line.xEnd, line.yEnd);
line
是一个包含行开头和结束值的对象。
我在那个图片框上画了10行。 我的mouse_Wheel监听器包含代码:
gfx.TranslateTransform((panelpreview.Width) / 2, (panelpreview.Height) / 2);
gfx.ScaleTransform(imageScale, imageScale);
gfx.TranslateTransform(-(panelpreview.Width) / 2, -(panelpreview.Height) / 2);
目前我正试图通过以下方式移动:
private void panelPreview_MouseDown(object sender, MouseEventArgs e)
{
if (e.Button == System.Windows.Forms.MouseButtons.Left)
{
checkLinesIntersection(e.Location); //checks if e.Location intersects with the line
panelPreview.MouseUp += new MouseEventHandler(panelPreview_MouseUpLine);
panelPreview.MouseMove += new MouseEventHandler(panelPreview_MouseMoveLine);
}
}
void panelPreview_MouseMoveLine(object sender, MouseEventArgs e)
{
if (_Leading.movable)
newFont.Leading = e.Y - (_base.yBegin + newFont._descenderHeight);
if (_xHeight.movable)
if (_base.yBegin - e.Y >= 0)
newFont.xHeight = _base.yBegin - e.Y;
if (_capHeight.movable)
if (_base.yBegin - e.Y >= 0)
newFont.capHeight = _base.yBegin - e.Y;
if (_ascenderHeight.movable)
if (_base.yBegin - e.Y >= 0)
newFont.ascenderHeight = _base.yBegin - e.Y;
if (_descenderHeight.movable)
if (e.Y - _base.yBegin >= 0)
newFont.descenderHeight = e.Y - _base.yBegin;
UpdatePreviewWindow();
}
void panelPreview_MouseUpLine(object sender, MouseEventArgs e)
{
panelPreview.MouseMove -= new MouseEventHandler(panelPreview_MouseMoveLine);
panelPreview.MouseUp -= new MouseEventHandler(panelPreview_MouseUpLine);
}
问题是,在放大后,即使在视觉上我按下线,但它没有反应它应该的方式。
public void checkLinesIntersection(Point mouseLocation)
{
lineIntersects(_Leading, mouseLocation);
lineIntersects(_xHeight, mouseLocation);
}
private void lineIntersects(nLine line, Point mouseLocation)
{
if (mouseLocation.X >= line.xBegin && mouseLocation.X <= line.xEnd)
if (mouseLocation.Y >= line.yBegin || mouseLocation.Y + 2 >= line.yBegin)
if (mouseLocation.Y <= line.yEnd || mouseLocation.Y - 2 <= line.yEnd)
switch (line.sName)
{
case "xHeight":
newFont.selectedLine = nFont.Lines._xHeight;
break;
default:
break;
}
}
答案 0 :(得分:0)
原来如此!在这个工具上工作了一段时间后,我改变了方法并使用XNA来处理图形(绘图,缩放,移动绘图对象)。
对我有很大帮助的是在XNA和Camera
中使用Matrix
进行转换。
无论如何!我不会发布我的XNA解决方案来处理这个问题但是通过使用XNA我找到了在WinForms中处理它的方法。
float Zoom = 1f;
Microsoft.Xna.Framework.Rectangle mouseRect;
Matrix inverse;
void TAB_PICTURE_BOX_MouseWheel(object sender, MouseEventArgs e)
{
try
{
if (e.Delta > 0)
{
Zoom+= .1f;
}
if (e.Delta < 0)
{
Zoom -= .1f;
}
gfx.ResetTransform();
gfx.TranslateTransform((Width + img.Width) / 2, (Height - img.Height) / 2);
gfx.ScaleTransform(Zoom, Zoom);
gfx.TranslateTransform(-(Width + img.Width) / 2, -(Height - img.Height) / 2);
getInversePosition(e);
}
catch (Exception ex)
{
Console.WriteLine(ex.Message);
}
}
最后触摸getInversePosition(e);
方法:
private void getInversePosition(MouseEventArgs e)
{
Matrix matrix = Matrix.CreateTranslation(new Vector3(-(Width + img.Width) / 2, -(Height - img.Height) / 2, 0)) *
Matrix.CreateScale(new Vector3(Zoom, Zoom, 1)) *
Matrix.CreateTranslation(new Vector3((Width + img.Width) / 2, (Height - img.Height) / 2, 0));
inverse = Matrix.Invert(matrix);
Vector2 mousePosition = Vector2.Transform(new Vector2(e.X, e.Y), inverse);
mouseRect = new Microsoft.Xna.Framework.Rectangle((int)mousePosition.X, (int)mousePosition.Y, 1, 1);
}
我确信有一种方法可以在没有XNA参与的情况下处理它但在我的场景中XNA完成了工作。