嗨,我有一个表,我在其中使用JSONB来存储嵌套的JSON数据,并且需要查询此JSONB列 下面是表格的结构
{
"id": "5810f6b3-fefb-4eb1-befc-7df11a24d997",
"entity": "LocationTypes",
"event_name": "LocationTypes added",
"data": {
"event":{
"id": "b2805163-78f0-4384-bad6-1df8d35b456d",
"name": "builidng",
"company_id": "1dd83f77-fdf1-496d-9e0b-f502788c3a7b",
"is_address_applicable": true,
"is_location_map_applicable": true}
},
"notes": null,
"event_time": "2020-11-05T10:56:34.909Z",
"company_id": "1dd83f77-fdf1-496d-9e0b-f502788c3a7b",
"created_at": "2020-11-05T10:56:34.909Z",
"updated_at": "2020-11-05T10:56:34.909Z"
}
下面的代码给出了空白数组作为响应
const dataJson = await database.activity_logs.findAll({
where: {
'data.event.id': {
$eq: 'b2805163-78f0-4384-bad6-1df8d35b456d',
},
},
raw: true,
});
有什么方法可以更好地使用sequelize完成对嵌套json对象的查询。
答案 0 :(得分:2)
您应该尝试sequelize.literal
并将JSON运算符/函数包装在sequelize.where
中。像这样:
sequelize.where(sequelize.literal("data->'event'->'id'"), '=', 'b2805163-78f0-4384-bad6-1df8d35b456d')