Question

当设备是pointerPressed方法中的触摸设备时，我想使用表格的选定行，而我得到的是错误的值：例如，我点击了第三行（PS：标题行是-1）我在System.out.println中得到0作为值！当我点击另一行时，我得到之前选择的行！那么如何将LWUIT与所选行同步？

Answer 1

好的，我找到了解决方案：在我写的构造函数中：

for (short idxComp=3; idxComp<tList.getComponentCount(); idxComp++)
        {
            tList.getComponentAt(idxComp).addFocusListener(this);
        }
isTableSelected = false;

以下是实施的方法：

public void pointerPressed(int x, int y)
    {
        int startX, startY, endX, endY, nbComps;
        nbComps = tList.getComponentCount();
        startX = tList.getComponentAt(3).getAbsoluteX();
        endX = tList.getComponentAt(5).getAbsoluteX() + tList.getComponentAt(5).getWidth();
        startY = tList.getComponentAt(3).getAbsoluteY();
        endY = tList.getComponentAt(nbComps-1).getAbsoluteY() + tList.getComponentAt(nbComps-1).getHeight();
        if ( (x >= startX && x <= endX) && (y >= startY && y <= endY) )
        {
            isTableSelected = true;
            if ( (x >= selectedComp.getAbsoluteX() && x <= (selectedComp.getAbsoluteX()+selectedComp.getWidth())) && (y >= selectedComp.getAbsoluteY() && y <= (selectedComp.getAbsoluteY()+selectedComp.getHeight())) )
                afficheFicheCredit(selectedRow);
        }
    }
    public void focusGained(Component comp) {
        tList.repaint();
        selectedComp = tList.getComponentAt(3*selectedRow+3);
        if (isTableSelected)
        {
            isTableSelected = false;
            selectedRow = tList.getSelectedRow();
            afficheFicheCredit(selectedRow);
        }
    }

错误的selectedRow返回了触摸设备

1 个答案: