我哪里可以犯错误?我需要点击插入数据库的按钮submitedRows。
$http.post("http://localhost/insert.php",{'isbn':$scope.submitedRows[0].isbn},{headers: {'Content-Type' : 'application/x-www-form-urlencoded; charset=UTF-8'}}).success(function(data,status,headers,config) {
console.log("data inserted successfully");
});
PHP代码我可以连接到db:
$db = mysqli_connect($host, $dbuser, $dbpass, $db);
$data = json_decode(file_get_contents("php://input"));
$isbn = mysqli_real_escape_string($db, $_POST['isbn']);
if(! $db )
{
die('Could not connect: ' . mysql_error());
}
$sql = "INSERT INTO deneme (isbn) VALUES ('".$isbn."');";
if (mysqli_query($db, $sql)) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . mysqli_error($db);
}