已经搜索了线程,但不了解可以解决我所拥有的数据帧问题的解决方案。
我当前的数据帧(df):
# A tibble: 8 x 29
`Athlete` Monday...2 Tuesday...3 Wednesday...4 Thursday...5 Friday...6 Saturday...7 Sunday...8
<chr> <chr> <chr> <chr> <chr> <chr> <chr> <chr>
1 Date 29/06/2020 30/06/2020 43837.0 43868.0 43897.0 43928.0 43958.0
2 HR 47.0 54.0 51.0 56.0 59.0 NA NA
3 HRV 171.0 91.0 127.0 99.0 77.0 NA NA
4 Sleep Duration 9.11 7.12 8.59 7.15 8.32 NA NA
5 Sleep Efficien~ 92.0 94.0 89.0 90.0 90.0 NA NA
6 Recovery Score 98.0 66.0 96.0 72.0 46.0 NA NA
7 Life Stress NO NO NO NO NO NA NA
8 Sick NO NO NO NO NO NA NA
已经尝试使用传播和更广泛地旋转,但我知道为了获得所需的输出,需要附加功能,这超出了我对R的理解。
我需要吗
所需的输出:
Date HR HRV Sleep Duration Sleep Efficiency Recovery Score Life Stress Sick
29/06/2020 47.0 171.0 9.11
30/06/2020 54.0 91.0 7.12
43837.0 51.0 127.0 8.59
43868.0 56.0 99.0 7.15
43897.0 59.0 77.0 8.32
43928.0 NA NA NA
43958.0 NA NA NA
等
谢谢
答案 0 :(得分:0)
在Base R中,您将执行以下操作:
type.convert(setNames(data.frame(t(df[-1]), row.names = NULL), df[,1]))
Date HR HRV Sleep Duration Sleep Efficien~ Recovery Score Life Stress Sick
1 29/06/2020 47 171 9.11 92 98 NO NO
2 30/06/2020 54 91 7.12 94 66 NO NO
3 43837.0 51 127 8.59 89 96 NO NO
4 43868.0 56 99 7.15 90 72 NO NO
5 43897.0 59 77 8.32 90 46 NO NO
6 43928 NA NA NA NA NA <NA> <NA>
7 43958 NA NA NA NA NA <NA> <NA>