Question

我正在尝试运行一个gui，其中提供了两个按钮。第一个是打印文件“ names.txt”的内容，第二个是绘制数据。但是，如果先绘制数据然后再打印内容，则子图将保持原样，并且无法清除。这是我的输出：[！[错误输出] [1]] 1 我阅读了帖子：Clear figure subplots matplotlib python并尝试了相同的操作，但是我没有得到正确的输出子图没有破坏。我什至尝试使用destroy self.scatter1.get_tk_widget().destroy()小部件，但这都不起作用有人可以告诉我如何进行吗？我的代码是：

import tkinter as tk
import matplotlib.pyplot as plt
from matplotlib.backends.backend_tkagg import FigureCanvasTkAgg
import random

x_loc=[5, 6, 34, 54, 23]
y_loc=[3, 4.34, 2, 44, 65]
avgLst=[24, 35.65, 54.6, 53, 2]
root= tk.Tk()

class graph_plot():
    global graph_past
    global graph_Avg
    
    def __init__(self):
        self.figure1 = plt.Figure()
        self.scatter1 = FigureCanvasTkAgg(self.figure1, root)
        self.scatter1.get_tk_widget().place(relx= 0.5, rely=0.1)
        self.subplot1 = self.figure1.add_subplot(111)
        self.subplot1.set_xlabel('x location')
        self.subplot1.set_ylabel('y location')
        
        
    def display_graph(self):
        data1 = {'x-locations' : x_loc , 'y_locations' : y_loc}
        df3 = DataFrame(data1,columns=['x-locations','y_locations'])
        global graph_past
        label2.config(text='')
        print('graph in= ' , graph_past)
        im0= self.subplot1.scatter(df3['x-locations'],df3['y_locations'], c=avgLst, cmap='rainbow', vmin=min(avgLst), vmax=max(avgLst))
        self.figure1.colorbar(im0)
        self.subplot1.set_title('Avg')
        graph_past= True
            
    def clear_graph(self):
        print('Destroyed!')
        self.subplot1.clear
        ## ??? which command


def do_graph():
    obj1 = graph_plot()
    obj1.display_graph()
   
def on_key(event):
    if myLine and event.keysym != 'Return':
        update_print()

def do_printing():
    global myLine
    global graph_past
    #print('graph_past= ' , graph_past)
    if graph_past:
        obj2 = graph_plot()
        obj2.clear_graph()
    graph_past = False
    input_File = open('names.txt','r')
    myLine = input_File.readlines()
    update_print()
    
def update_print():
    label2.config(text=random.choice(myLine))
  
def flag_print():
    global graph_Avg
    graph_Avg=False
    do_printing()

def flag_Avg():
    global graph_Avg
    graph_Avg=True
    do_graph()

root.bind('<Key>', on_key)

myCanvas = tk.Canvas(root, width = 800, height = 500)
myCanvas.grid(row=2, column= 4)

label1 = tk.Label(root, text='MENU')
label1.config(font=('Arial', 20))
myCanvas.create_window(200, 20, window=label1)
myLine= None
graph_Avg=False
graph_past=False

label2 = tk.Label(root, font=('Courier', 15))
label2.place(relx= 0.3, rely=0.1)

B1 = tk.Button(root, text ="Option 1", font=('Courier', 12), command = flag_print)
myCanvas.create_window(200, 100, window=B1)

B2 = tk.Button(root, text ="Option 2", font=('Courier', 12), command = flag_Avg)
myCanvas.create_window(200, 140, window=B2)

root.mainloop()```


  [1]: https://i.stack.imgur.com/RgL7S.png

Answer 1

尝试用self.subplot1.clear()代替self.subplot1.destroy()

Answer 2

问题

问题是由于在FigureCanvasTkAgg类的__init__()方法中创建了多个graph_plot对象。在do_graph()和do_printing()方法中调用了此构造函数，这意味着许多相同的画布正在彼此之上创建。这意味着当您.destroy()窗口小部件时，它将破坏一个新窗口小部件，并将其留在下面。

解决方案

解决方案是，如果您要继续使用类，则将更多的变量提升为全局变量，这样就可以确保您在处理相同的对象，而不是单独的对象。最好是完全重新考虑使用类来解决此问题。

代码我将您的一些代码重组为避开了类并获得了预期的结果：

import tkinter as tk
import matplotlib.pyplot as plt
from pandas import DataFrame
from matplotlib.backends.backend_tkagg import FigureCanvasTkAgg
import random

x_loc=[5, 6, 34, 54, 23]
y_loc=[3, 4.34, 2, 44, 65]
avgLst=[24, 35.65, 54.6, 53, 2]

GRAPH_AVG=False
GRAPH_PAST=False
MY_LINE = None


ROOT = tk.Tk()
ROOT.geometry("900x600")
FIGURE = plt.Figure()
SCATTER = FigureCanvasTkAgg(FIGURE, ROOT)

TK_WIDGET = SCATTER.get_tk_widget()

SUBPLOT = FIGURE.add_subplot(111)
SUBPLOT.set_xlabel('x location')
SUBPLOT.set_ylabel('y location')

NAME_LABEL = tk.Label(ROOT, font=('Courier', 15))
NAME_LABEL.place(relx=0.3, rely=0.1)
        
def display_graph():
    global GRAPH_PAST, FIGURE, SUBPLOT

    data1 = {'x-locations' : x_loc , 'y_locations' : y_loc}
    df3 = DataFrame(data1, columns=['x-locations','y_locations'])
    NAME_LABEL.config(text='')
    print('graph past= ' , GRAPH_PAST)
    im0= SUBPLOT.scatter(df3['x-locations'],df3['y_locations'], c=avgLst, cmap='rainbow', vmin=min(avgLst), vmax=max(avgLst))
    FIGURE.colorbar(im0)
    SUBPLOT.set_title('Avg')
    TK_WIDGET.place(relx=0.3, rely=0.1)
    GRAPH_PAST= True
        
def clear_graph():
    global SUBPLOT, TK_WIDGET
    print('Destroyed!')
    SUBPLOT.clear()
    TK_WIDGET.place_forget()

   
def on_key(event):
    global MY_LINE
    if MY_LINE and event.keysym != 'Return':
        update_print()

def do_printing():
    global MY_LINE, GRAPH_AVG, GRAPH_PAST

    if GRAPH_PAST:
        clear_graph()
    GRAPH_PAST = False
    MY_LINE = ["john kenny", "maria rose", "sheena"]
    update_print()
    
def update_print():
    NAME_LABEL.config(text=random.choice(MY_LINE))
  
def flag_print():
    global GRAPH_AVG
    GRAPH_AVG=False
    do_printing()

def flag_Avg():
    global GRAPH_AVG
    GRAPH_AVG=True
    display_graph()


ROOT.bind('<Key>', on_key)

B1 = tk.Button(ROOT, text ="Print", font=('Courier', 12), command=flag_print)
B1.place(relx=0.1, rely=0.1)

B2 = tk.Button(ROOT, text ="Graph", font=('Courier', 12), command=flag_Avg)
B2.place(relx=0.1, rely=0.2)

ROOT.mainloop()

如何在Tkinter的matplotlib中删除/清除子图和画布（白色窗口-FigureCanvasTkAgg）？

2 个答案: