在片段之间共享数据

时间:2020-02-22 21:53:59

标签: android android-fragments mvvm viewmodel android-viewmodel

我正在android上制作一个bugtracker应用程序,其中有一个名为Task的类,该类具有一个“类别”字段,用于定义任务是否完成,正在进行或必须执行。

我在其中添加了一个想法片段“项目”,用于设置ViewModel

y=-x^2

在观察变化的相应类别中,我也有3个片段。

public class ProjectFragment extends Fragment {

private static final String TAG = "ProjectFragment";

private UserViewModel model;
private GridViewAdapter gridViewAdapter;

@Nullable
@Override
public View onCreateView(@NonNull LayoutInflater inflater, @Nullable ViewGroup container, @Nullable Bundle savedInstanceState) {

    View view = inflater.inflate(R.layout.fragment_projects, container, false);

    model = ViewModelProviders.of(requireActivity()).get(UserViewModel.class);
    GridView gridView = view.findViewById(R.id.gridview_project);
    gridView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
            Project temp = Objects.requireNonNull(model.getCurrentuser().getValue()).getProjects().get(position);
            model.setCurrproject(temp);
            Log.i(TAG, "onItemClick: " + temp.getProjectName());
            model.setTodoTasks(TaskSorter.getSortedTaskList(temp, "TODO"));
            model.setInprogressTasks(TaskSorter.getSortedTaskList(temp, "IN PROGRESS"));
            model.setDoneTasks(TaskSorter.getSortedTaskList(temp, "DONE"));

        }
    });
    gridViewAdapter = new GridViewAdapter(requireActivity(), Objects.requireNonNull(model.getCurrentuser().getValue()).getProjects());
    gridView.setAdapter(gridViewAdapter);
    model.getCurrentuser().observe(this, new Observer<User>() {
        @Override
        public void onChanged(User user) {
            gridViewAdapter.notifyDataSetChanged();

        }
    });

    FloatingActionButton floatingActionButton = view.findViewById(R.id.floatingActionButton);
    floatingActionButton.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            openProjectDialog();
        }
    });

    return view;
}

所有3个片段看起来都是这样,当然名称也不同。每当我单击一个项目时,都会发生某些更改,但并非全部更改。这三个类别由ViewPager保留,但是我不确定问题出在哪里。如果也有以下代码:

public class FragmentToDo extends Fragment {

private static final String TAG = "FragmentToDo";

private ListView listView;
private UserViewModel model;
private ListViewAdapter listViewAdaptertodo;


@Nullable
@Override
public View onCreateView(@NonNull LayoutInflater inflater, @Nullable ViewGroup container, @Nullable Bundle savedInstanceState) {
    View view = inflater.inflate(R.layout.fragment_todo, container, false);
    listView = view.findViewById(R.id.todo_list);
    model = ViewModelProviders.of(this).get(UserViewModel.class);
    model.gettodoTasks().observe(this, new Observer<ArrayList<Task>>() {
        @Override
        public void onChanged(ArrayList<Task> tasks) {
            listViewAdaptertodo.notifyDataSetChanged();
            Log.i(TAG, "onChanged: todo");
        }
    });
    initTodo();
    return view;
}

private void initTodo(){
    listViewAdaptertodo = new ListViewAdapter(requireActivity(), model.gettodoTasks().getValue());
    listView.setAdapter(listViewAdaptertodo);
    listView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
            openTask();
        }
    });
}

}

也许问题出在我定义上下文和生命周期所有者的时候,因为我是一名Android新手,所以我对这些主题仍然一无所知。

1 个答案:

答案 0 :(得分:0)

有一种简单且不可扩展的方法-例如,事件总线this

首选方法-将应用程序逻辑从片段移动到其他组件,而数据仅以一种方式传递。即有一个组件,它暴露了屏幕的某种模型,并进行了更新-片段/视图/活动反映了这一变化。您可以检查示例应用here