Question

我正在制作一个小型2d游戏，目标是尽可能吃掉大便，但是我在随机时间生成大便时遇到了麻烦。我希望大便在敌人的y位置生成，然后像rpg一样向前射击。

import pygame
from pygame.locals import *
from numpy.random import rand

pygame.init()
pygame.display.set_caption('STINKY BEETLE')

screen_width = 800
screen_height = 600
game_running = True
pl_x = int(screen_width/10)
pl_y = int(screen_height/2)
pl_width = 80
pl_height = 40
pl_vel = 30
en_width = 80
en_height = 40
en_x = screen_width - screen_width/10 - en_width
en_y = int(screen_height/2)
en_yvel = -10
po_width = 50
po_height = 30
po_x = 720
po_y = en_y
po_xvel = 15

screen = pygame.display.set_mode((screen_width, screen_height))
clock = pygame.time.Clock()

while game_running:
    clock.tick(10)

    po_delay = rand(1)

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            game_running = False

        if event.type == MOUSEBUTTONDOWN:
            if event.button == 4 and pl_y > pl_vel:
                pl_y -= pl_vel

            elif event.button == 5 and pl_y < screen_height - pl_width:
                pl_y += pl_vel

    if po_delay < 0.01:
        poop(po_x, po_y)

    en_y += en_yvel
    if en_y <= 0 or en_y >= screen_height - en_height:
        en_yvel =- en_yvel

    screen.fill((0, 0, 0))
    pygame.draw.rect(screen, (105, 255, 125), (pl_x, pl_y, pl_width, pl_height))
    pygame.display.update()

    pygame.draw.rect(screen, (255, 125, 115), (en_x, en_y, en_width, en_height))
    pygame.display.update()

pygame.quit()

Answer 1

如果要管理多个“便便”，则必须创建一个列表。而且每个“便便”都是一个对象（class的实例）。

创建一个类Poop，该类可以update的位置和draw的便便：

class Poop:
    def __init__(self, x, y, w, h):
        self.rect = pygame.Rect(x, y-h//2, w, h)
        self.vel = -15
    def update(self):
        self.rect.x += self.vel
    def draw(self, surf):
        pygame.draw.rect(surf, (255, 200, 125), self.rect)

poops = []

使用计时器事件生成便便。使用pygame.time.set_timer()重复创建USEREVENT。时间以毫秒为单位设置。通过random.randint(a, b)设置随机时间，例如将时间设置为0.5到4秒（当然，您可以选择自己的时间间隔）：

min_time, max_time = 500, 4000 # 0.5 seconds to to 4 seconds
spawn_event = pygame.USEREVENT + 1
pygame.time.set_timer(spawn_event, random.randint(min_time, max_time))

注意，可以在pygame中定义客户事件。每个事件都需要一个唯一的ID。用户事件的ID必须以pygame.USEREVENT开头。在这种情况下，pygame.USEREVENT+1是计时器事件的事件ID，它会生成便便。

当事件在事件循环中发生时创建一个新的便便并设置一个新的随机时间：

for event in pygame.event.get():
    # [...]
    if event.type == spawn_event:
        pygame.time.set_timer(spawn_event, random.randint(min_time, max_time))
        poops.append(Poop(en_x, en_y+en_yvel+en_height//2, 50, 30))

更改大便在循环中的位置，如果它们离开左侧窗口，则将其从列表中删除：

for poop in poops[:]:
    poop.update()
    if poop.rect.right <= 0:
        poops.remove(poop)

在循环中绘制它们

for poop in poops:
    poop.draw(screen)

查看示例：

import pygame
from pygame.locals import *
import random

pygame.init()
pygame.display.set_caption('STINKY BEETLE')

class Poop:
    def __init__(self, x, y, w, h):
        self.rect = pygame.Rect(x, y-h//2, w, h)
        self.vel = -15
    def update(self):
        self.rect.x += self.vel
    def draw(self, surf):
        pygame.draw.rect(surf, (255, 200, 125), self.rect)

screen_width = 800
screen_height = 600
game_running = True
pl_x, pl_y = screen_width//10, screen_height//2
pl_width, pl_height, pl_vel = 80, 40, 30
en_width, en_height, en_yvel = 80, 40, -10
en_x, en_y,  = screen_width - screen_width//10 - en_width, screen_height//2

screen = pygame.display.set_mode((screen_width, screen_height))
clock = pygame.time.Clock()

min_time, max_time = 500, 4000 # 0.5 seconds up to 4 seconds 
spawn_event = pygame.USEREVENT + 1
pygame.time.set_timer(spawn_event, random.randint(min_time, max_time))
poops = []

while game_running:
    clock.tick(10)

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            game_running = False

        if event.type == MOUSEBUTTONDOWN:
            if event.button == 4 and pl_y > pl_vel:
                pl_y -= pl_vel
            elif event.button == 5 and pl_y < screen_height - pl_width:
                pl_y += pl_vel

        if event.type == spawn_event:
            pygame.time.set_timer(spawn_event, random.randint(min_time, max_time))
            poops.append(Poop(en_x, en_y+en_yvel+en_height//2, 50, 30))

    en_y += en_yvel
    if en_y <= 0 or en_y >= screen_height - en_height:
        en_yvel =- en_yvel

    for poop in poops[:]:
        poop.update()
        if poop.rect.right <= 0:
            poops.remove(poop)

    screen.fill((0, 0, 0))
    for poop in poops:
        poop.draw(screen)
    pygame.draw.rect(screen, (105, 255, 125), (pl_x, pl_y, pl_width, pl_height))
    pygame.draw.rect(screen, (255, 125, 115), (en_x, en_y, en_width, en_height))
    pygame.display.update()

pygame.quit()

Answer 2

您可以使用pygame的时间模块随机生成敌人。我假设您为此使用OOP。首先，在初始化敌方职业时，记录其第一次产生的时间。

class Enemy:
    def __init__(self):
        self.start = time.time()
        # other code

然后，您可以计算自敌人最后一次屈服以来经过的时间。您可以在主游戏循环中进行类似now = time.time()的操作并获得不同。

enemy = Enemy()
while True:
    now = time.time()
    time_passed = now - enemy.start()

现在，您可以将此time_passed用作您可能创建的spawn_enemy()函数的参数，该函数看起来像这样：

def spawn(self, t):
   counter = t % random.randint(1, 10)
   if counter >= 0 and counter <=  0.2:
       #spawn enemy

将该函数称为spawn(time_passed)

随机产生一个敌人

2 个答案: