我有一个包含名称值对的varchar(max)
字段,在每行中都有名称UnderScore Value。
我需要对它进行查询,以便它返回两列中的Name,Value对(因此通过解析文本,删除下划线和“new line”char。
所以从这个
select NameValue from Table
我收到此文:
Name1_Value1
Name2_Value2
Name3_Value3
我想有这个输出
Names Values
===== ======
Name1 Value1
Name2 Value2
Name3 Value3
答案 0 :(得分:6)
SELECT substring(NameValue, 1, charindex('_', NameValue)-1) AS Names,
substring(NameValue, charindex('_', NameValue)+1, LEN(NameValue)) AS Values
FROM Table
修改强>:
将这样的函数或存储过程与临时表结合起来应该适用于多行,具体取决于行分隔符,您还应该在开始之前删除CHAR(13)
:
DECLARE @helper varchar(512)
DECLARE @current varchar(512)
SET @helper = NAMEVALUE
WHILE CHARINDEX(CHAR(10), @helper) > 0 BEGIN
SET @current = SUBSTRING(@helper, 1, CHARINDEX(CHAR(10), NAMEVALUE)-1)
SELECT SUBSTRING(@current, 1, CHARINDEX('_', @current)-1) AS Names,
SUBSTRING(@current, CHARINDEX('_', @current)+1, LEN(@current)) AS Names
SET @helper = SUBSTRING(@helper, CHARINDEX(CHAR(10), @helper)+1, LEN(@helper))
END
SELECT SUBSTRING(@helper, 1, CHARINDEX('_', @helper)-1) AS Names,
SUBSTRING(@helper, CHARINDEX('_', @helper)+1, LEN(@helper)) AS Names
答案 1 :(得分:2)
DECLARE @TExt NVARCHAR(MAX)= '***[ddd]***
dfdf
fdfdfdfdfdf
***[fff]***
4545445
45454
***[ahaASSDAD]***
DFDFDF
***[SOME TEXT]***
'
DECLARE @Delimiter VARCHAR(1000)= CHAR(13) + CHAR(10) ;
WITH numbers
AS ( SELECT ROW_NUMBER() OVER ( ORDER BY o.object_id, o2.object_id ) Number
FROM sys.objects o
CROSS JOIN sys.objects o2
),
c AS ( SELECT Number CHARBegin ,
ROW_NUMBER() OVER ( ORDER BY number ) RN
FROM numbers
WHERE SUBSTRING(@text, Number, LEN(@Delimiter)) = @Delimiter
),
res
AS ( SELECT CHARBegin ,
CAST(LEFT(@text, charbegin) AS NVARCHAR(MAX)) Res ,
RN
FROM c
WHERE rn = 1
UNION ALL
SELECT c.CHARBegin ,
CAST(SUBSTRING(@text, res.CHARBegin,
c.CHARBegin - res.CHARBegin) AS NVARCHAR(MAX)) ,
c.RN
FROM c
JOIN res ON c.RN = res.RN + 1
)
SELECT *
FROM res
答案 2 :(得分:0)
他是一个你可以使用的例子:
-- Creating table:
create table demo (dID int, dRec varchar(100));
-- Inserting records:
insert into demo (dID, dRec) values (1, 'BCQP1 Sam');
insert into demo (dID, dRec) values (2, 'BCQP2 LD');
-- Selecting fields to retrive records:
select * from demo;
然后我想在一行中显示两行合并,只显示左侧的值,删除右侧的名称,直到空格字符。
/*
The STUFF() function puts a string in another string, from an initial position.
The LEFT() function returns the left part of a character string with the specified number of characters.
The CHARINDEX() string function returns the starting position of the specified expression in a character string.
*/
SELECT
DISTINCT
STUFF((SELECT ' ' + LEFT(dt1.dRec, charindex(' ', dt1.dRec) - 1)
FROM demo dt1
ORDER BY dRec
FOR XML PATH('')), 1, 1, '') [Convined values]
FROM demo dt2
--
GROUP BY dt2.dID, dt2.dRec
ORDER BY 1
正如您在运行该函数时所看到的那样,输出将是:
BCQP1 BCQP2
在脚本的顶部,我解释了每个函数的用途(STUFF(),LEFT(),CHARINDEX()函数)我还使用了DISTINCT来消除重复值。
注意:dt代表"演示表",我使用相同的表并使用两个别名dt1和dt2,而dRec代表"演示记录"
如果您想了解更多有关STUFF()的信息,请点击此链接:
答案 3 :(得分:-1)
使用CTE,如果超过100项
,则会出现递归问题Msg 530,Level 16,State 1,Line 20声明终止。该 在语句完成之前,最大递归100已经用尽。
DECLARE @TExt NVARCHAR(MAX)
SET @TExt = '100,101,102,103,104,105,106,107,108,109,110,111,112,113,114,115,116,117,118,119,120,121,122,123,124,125,126,127,128,129,130,131,132,133,134,135,136,137,138,139,140,141,142,143,144,145,146,147,148,149,150,151,152,153,154,155,156,157,158,159,160,161,162,163,164,165,166,167,168,169,170,171,172,173,174,175,176,177,178,179,180,181,182,183,184,185,186,187,188,189,190,191,192,193,194,195,196,197,198,199,200,201,202,203'
DECLARE @Delimiter VARCHAR(1000)= ',';
WITH numbers
AS ( SELECT ROW_NUMBER() OVER ( ORDER BY o.object_id, o2.object_id ) Number
FROM sys.objects o
CROSS JOIN sys.objects o2
),
c AS ( SELECT Number CHARBegin ,
ROW_NUMBER() OVER ( ORDER BY number ) RN
FROM numbers
WHERE SUBSTRING(@text, Number, LEN(@Delimiter)) = @Delimiter
),
res
AS ( SELECT CHARBegin ,
CAST(LEFT(@text, charbegin) AS NVARCHAR(MAX)) Res ,
RN
FROM c
WHERE rn = 1
UNION ALL
SELECT c.CHARBegin ,
CAST(SUBSTRING(@text, res.CHARBegin,
c.CHARBegin - res.CHARBegin) AS NVARCHAR(MAX)) ,
c.RN
FROM c
JOIN res ON c.RN = res.RN + 1
)
SELECT *
FROM res