Python从熊猫列转换为列表吗？

Question

我想知道我是否具有以下格式的文件 我想将每一列都放在列表列表中，因为我有多个句子： 所以输出看起来像这样

[['Learning centre of The University of Lahore is established for professional development.'], 
 ['These events, destroyed the bond between them.']]

，动词列也是如此。这是我尝试过的方法，但是它将所有内容都放在一个列表中，而不是列表列表中

train_fn="/content/data/wiki/wiki1.train.oie"


dfE = pandas.read_csv(train_fn, sep= "\t",
                         header=0,
                         keep_default_na=False)
train_textEI = dfE['word'].tolist()
train_textEI = [' '.join(t.split()) for t in train_textEI]
train_textEI = np.array(train_textEI, dtype=object)[:, np.newaxis]

它输出列表中的每个单词

[['Learning'],['Center'],['of'],['The'],['University'],['of'],
 ['Lahore'],['is'],['established'],['for'],['the'],
 ['professional'],['development'],['.'],['These'],['events'],[','],
 ['destroyed'],['the'],['bond'],['between'],['them'],['.']]

Answer 1

通过将Series.eq的Series与Series.cumsum，word_id和groupby进行比较来创建助手Series并转换为列表，最后将输出df = pd.DataFrame({'word_id':[0,1,2,0,1], 'word':['a s','ds d','sss dd','d','sd ds']}) L = df.groupby(df['word_id'].eq(0).cumsum())['word'].apply(lambda x: [' '.join(x)]).tolist() print (L) [['a s ds d sss dd'], ['d sd ds']] 转换为列表：

mvvm