这是我的JSON,当我阅读ord时,uniq数据我收到错误
let response2 : [String: Any] = ["Response":["status":"SUCCESS","error_code":"0","message":"SUCCESS","Array":[
["ord":"50","uniq":"5a66c2348",
"name":"SHREE","no":"UP11AT0","loc":"Hathin","lat":"23.33","lon":"87.09","date":"30-01-2018","time":"12:35:33","dis_dt":"00-00-0000","dis_tm":"00:00:00"],
["ord":"50","uniq":"5a66c2348",
"name":"SHREE","no":"UP11AT0","loc":"Hathin","lat":"23.33","lon":"87.09","date":"30-01-2018","time":"12:35:33","dis_dt":"00-00-0000","dis_tm":"00:00:00"],
["ord":"50","uniq":"5a66c2348",
"name":"SHREE","no":"UP11AT0","loc":"Hathin","lat":"23.33","lon":"87.09","date":"30-01-2018","time":"12:35:33","dis_dt":"00-00-0000","dis_tm":"00:00:00"]
]],"count":"35"]
我的代码是
let status = "\((response2["Response"]! as! [String: Any])["status"]!)"
print(status)
if status == "SUCCESS" {
let count = ((response2["Response"]! as! [String: Any])["Array"] as AnyObject).count!
print(count)
let ar = (response2["Response"]! as! [String: Any])["Array"]!
print(ar)
var ord_id: [Any] = []
for i in 0..<count {
ord_id.append((response2["Response"]! as! [String: Any])["Array"]! [0] as! [String:Any])// Here I'm getting Type 'Any' has no subscript members and
}
} else {
print("Show alert")
}
写这样的时候我收到错误: 类型'任何'没有下标成员
let ar = (response2["Response"]! as! [String: Any])["Array"]! [0] as! [String: Any]
当我写这样的错误时: 无法转换类型'Swift.Array&gt;'的值(0x10bf341f0)到'Swift.Dictionary'(0x10bf340d0)。
let ar = (response2["Response"]! as! [String: Any])["Array"]! as! [String: Any]
我无法理解如何解决它的确切问题。
答案 0 :(得分:1)
要计算,你需要做...
if let res = response2["Response"] as? [String: Any], let arr = res["Array"] as? [[String: Any]] {
print("array count = \(arr.count)")
} else {
print("Array not found !!")
}
从“响应”键获取数组...
var ord_id: [Any] = []
if let res = response2["Response"] as? [String: Any] {
if let arr = res["Array"] as? [Any], arr.count > 0 {
print(arr)
ord_id = arr
}
}
修改强>
要获得“old”和“uniq”键值,您需要通过一个数组并获取所需的对象。
var ordId_arr = [String]()
var uniq_arr = [String]()
for obj in ord_id {
print(obj)
if let dict = obj as? [String: Any] {
//print(dict["ord"] as! String)
//print(dict["uniq"] as! String)
//print(dict["name"] as! String)
//you can get other values in same way
if let ord = dict["ord"] as? String {
ordId_arr.append(ord)
}
if let uniq = dict["uniq"] as? String {
uniq_arr.append(uniq)
}
}
}
print("\(ordId_arr)")
print("\(uniq_arr)")
答案 1 :(得分:1)
Parse可以通过,也可以使用Decodable
将JSON解析为对象。
let response = response2["Response"]! as! [String: Any]
let status = response["status"]!
if let array = response["Array"] as? Array<Dictionary<String, Any>> {
print(array.count)
let ordArray = array.map { $0["ord"] }
let unique = Array(Set(ordArray)) //Do if needs to stripe duplicates
let uniqArray = array.map { $0["uniq"] }
print(ordArray)
print(uniqArray)
}