无法转换类型'Swift.Array＆lt;（Swift.String，Swift.String）＆gt;'的值到'Swift.AnyObject'

Question

我的swift代码如下所示

Family.arrayTuple:[(String,String)]? = []
Family.arrayTupleStorage:String?
Family.arrayTupleStorage:String = (newDir! as NSString).stringByAppendingPathComponent("arrayTuple.archive")
NSKeyedArchiver.archiveRootObject(Family.arrayTuple! as! AnyObject, toFile: Family.arrayTupleStorage!)

我在构建代码时在控制台窗口中有错误按摩。

  

'无法转换类型'Swift.Array＆lt;（Swift.String，Swift.String）＆gt;'的值（0xcce8098）到'Swift.AnyObject'（0xcc8f00c）。'

如何归档Family.arrayTuple并取消归档Family.arrayTupleStorage？

Answer 1

class ViewController: UIViewController {
    override func viewDidLoad() {
        super.viewDidLoad()

        let obj = SomeClass()
        obj.foo = (6,5)

        let data = NSKeyedArchiver.archivedDataWithRootObject(obj)
        NSUserDefaults.standardUserDefaults().setObject(data, forKey: "books")

        if let data = NSUserDefaults.standardUserDefaults().objectForKey("books") as? NSData {
            let o = NSKeyedUnarchiver.unarchiveObjectWithData(data) as SomeClass
            println(o.foo) // (Optional(6), Optional(5))

        }
    }
}

class SomeClass: NSObject, NSCoding {
    var foo: (x: Int?, y: Int?)!

    required convenience init(coder decoder: NSCoder) {
        self.init()
        let x = decoder.decodeObjectForKey("myTupleX") as Int?
        let y = decoder.decodeObjectForKey("myTupleY") as Int?
        foo = (x,y)
    }

    func encodeWithCoder(coder: NSCoder) {
        coder.encodeObject(foo.x, forKey: "myTupleX")
        coder.encodeObject(foo.y, forKey: "myTupleY")
    }
}